9514 1404 393
Answer:
38.5°
Step-by-step explanation:
You are given all three side lengths of the relevant triangle, so the Law of Cosines can be used to find any desired angle. If we call the desired angle C, then that law tells you ...
C = arccos((a² +b² -c²)/(2ab))
where a and b are the triangle side lengths adjacent to the angle of interest, and c is the side opposite. Here, 'a' and 'b' are the pole and cable lengths, and 'c' is the distance of the stake from the pole.
C = arccos((35² +48² -30²)/(2·35·48)) = arccos(2629/3360)
C ≈ 38.515°
The cable makes an angle of about 38.5° with the pole.
Your answer for this is C
A line perpendicular to y = (1/4)x+3 will have slope -4.
<span>This is because when you multiply the slopes of the original line and the perpendicular line, you get -1. (1/4)(-4)=-1 </span>
<span>The equation of the perpendicular line is </span>
<span>y=-4x+b </span>
<span>This line pases through (0,6) </span>
<span>6=-4(0)+b </span>
<span>b=6 </span>
<span>y=-4x+6 is the line </span>
The length of line segment EC is 35