2х - Зу = – 24<br>put it in slope form

Work out the diffeence beteeen 77.5 and 2.27

Stella [2.4K]

77.5
- 2.27
______
75.37

6 0

3 years ago

Read 2 more answers

Solve 90x = 81+25x^2

qwelly [4]

Answer:

1.8

Step-by-step explanation:

Solve for x

90

x

=

81

+

25

x

2

Subtract

25

x

2

from both sides of the equation.

90

x

−

25

x

2

=

81

Subtract

81

from both sides of the equation.

90

x

−

25

x

2

−

81

=

0

Factor the left side of the equation.

Tap for more steps...

−

(

5

x

−

9

)

2

=

0

Multiply each term in

−

(

5

x

−

9

)

2

=

0

by

−

1

Tap for more steps...

(

5

x

−

9

)

2

=

0

Set the

5

x

−

9

equal to

0

.

5

x

−

9

=

0

Solve for

x

.

Tap for more steps...

x

=

9

5

The result can be shown in multiple forms.

Exact Form:

x

=

9

5

Decimal Form:

x

=

1.8

Mixed Number Form:

x

=

1

4

5

Upgrade to

6 0

3 years ago

What is the volume of the cone with a height of 3ft and a radius of 4 ft in cubic ft

tino4ka555 [31]

The answer is 50.24 ft

4 0

3 years ago

Is the question asking to see if x = 1, y=-2, and z=2 by solving the three equations?

dybincka [34]

Answer:

2 × 1 +2 +2×2 =8

2+2+4=8

8=8

3×1 +3× -2 + 4×2 =5

3-6+8=5

5=5

1+2 × -2 +2 = -5

1-4+2= -5

-5 = -5

6 0

2 years ago

Which of the following are identities? Check all that apply

Natasha2012 [34]

Answer:

A, C

Step-by-step explanation:

Actually, those questions require us to develop those equations to derive into trigonometrical equations so that we can unveil them or not. Doing it only two alternatives, the other ones will not result in Trigonometrical Identities.

Examining

A) True

$\frac{1-tan^{2}x}{2tanx} =\frac{1}{tan2x} \\ \frac{1-tan^{2}x}{2tanx} =\frac{1}{\frac{2tanx}{1-tan^{2}x}}\\ tan2x=\frac{1-tan^{2}x}{2tanx}$

Double angle $tan2\alpha =\frac{1 -tan^{2}\alpha }{2tan\alpha}$

B) False,

No further development towards a Trig Identity

C) True

Double Angle Sine Formula $sin2\alpha =2sin\alpha *cos\alpha$

$sin(8x)=2sin(4x)cos(4x)\\2sin(4x)cos(4x)=2sin(4x)cos(4x)$

D) False No further development towards a Trig Identity

$[sin(x)-cos(x)]^{2} =1+sin(2x)\\ sin^{2} (x)-2sin(x)cos(x)+cos^{2}x=1+2sinxcosx\\ \\sin^{2} (x)+cos^{2}x=1+4sin(x)cos(x)$

7 0

3 years ago

Read 2 more answers

2х - Зу = – 24put it in slope form​

2х - Зу = – 24put it in slope form