Solve -23 equals x minus 23

Find the maximum value of the function for the polygonal convex set determined by the given system of inequalities.

V125BC [204]

Answer:

A. at (8,7) the maximum value is 98

Step-by-step explanation:

First draw the region, that is bounded by all

inequalities. This is the triangle with vertices

(6,1), (2,5) and (8,7).

Now you can see where the line f(x,y)=7x+6y

intersect this region. The maximum value will be

at endpoints of this region:

• at (6,1), f(6,1)=7-6+6-1=42+6=48;

·

at (2,5), f(2,5)=7·2+6.5=14+30=44;

• at (8,7), f(8,7)=7.8+6-7=56+42=98.

Thus, the maximum value of the function is 98 at

the point (8,7).

frika. Quality Assurance

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8 0

2 years ago

Which of the numbers listed below are solutions to the equation?

Savatey [412]

5, and -5 because a negative times a negative equals a positive

7 0

3 years ago

Read 2 more answers

Each week, Heather’s company has $5000 in fixed costs plus an additional $250 for each system produced. The company is able to p

kvv77 [185]

The question is an illustration of composite functions.

Functions c(n) and h(n) are $\mathbf{c(n) = 5000 + 250n}$ and $\mathbf{n(h) = 5h}$
The composite function c(n(h)) is $\mathbf{c(n(h)) = 5000 + 1250h}$
The value of c(n(100)) is $\mathbf{c(n(100)) = 130000}$
The interpretation is: "the cost of working for 100 hours is $130000"

The given parameters are:

$5000 in fixed costs plus an additional $250
5 systems in one hour of production

(a) Functions c(n) and n(h)

Let the number of system be n, and h be the number of hours

So, the cost function (c(n)) is:

$\mathbf{c(n) = Fixed + Additional \times n}$

This gives

$\mathbf{c(n) = 5000 + 250 \times n}$

$\mathbf{c(n) = 5000 + 250n}$

The function for number of systems is:

$\mathbf{n(h) = 5 \times h}$

$\mathbf{n(h) = 5h}$

(b) Function c(n(h))

In (a), we have:

$\mathbf{c(n) = 5000 + 250n}$

$\mathbf{n(h) = 5h}$

Substitute n(h) for n in $\mathbf{c(n) = 5000 + 250n}$

$\mathbf{c(n(h)) = 5000 + 250n(h)}$

Substitute $\mathbf{n(h) = 5h}$

$\mathbf{c(n(h)) = 5000 + 250 \times 5h}$

$\mathbf{c(n(h)) = 5000 + 1250h}$

(c) Find c(n(100))

c(n(100)) means that h = 100.

So, we have:

$\mathbf{c(n(100)) = 5000 + 1250 \times 100}$

$\mathbf{c(n(100)) = 5000 + 125000}$

$\mathbf{c(n(100)) = 130000}$

(d) Interpret (c)

In (c), we have: $\mathbf{c(n(100)) = 130000}$

It means that:

The cost of working for 100 hours is $130000

Read more about composite functions at:

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5 0

3 years ago

Figure A has a radius of 2 inches. It is dilated by a scale factor of 4 to form figure B. What is the radius of figure B?

snow_lady [41]

Given that figure A with radius of 2 inches is dilated to form figure B, the radius of B will be given by:
Radius B=(radius A)×(scale factor)
but
scale factor=4
thus
Radius of B will be:
2×4
=8 inches

7 0

3 years ago

Kwan hiked up a hill at 4 km/h and back down at 6 km/h. His total hiking time was 3 hours. How long did the trip up the hill tak

Leya [2.2K]

Let the time to hike up the hill = t

As given that the total time time up and down is 3 hrs, therefore

The time down the hill = 3-t

The distance up and down is the same.

Distance = speed * time

$4t=6(3-t)$