It's 10.
Mass = density x volume
M = 1g/ml(10ml) = 10g
Answer:
<em>think</em><em> </em><em>it's</em><em> </em><em>B</em>
Explanation:
Gravity is a force of attraction that exists between any two masses, any two bodies, any two particles. Gravity is not just the attraction between objects and the Earth. It is an attraction that exists between all objects, everywhere in the universe.
<em>H</em><em>o</em><em>p</em><em>e</em><em> </em><em>it'll</em><em> </em><em>help</em><em>!</em>
<em>s</em><em>t</em><em>a</em><em>y</em><em> </em><em>safe</em><em>:</em><em>)</em><em> </em><em>^</em><em>-</em><em>^</em>
Hello!
There are two tests one could use to identify a solution of Ag₃PO₄ (keep in mind that this compound is very insoluble and very little amounts of it are in solution)
For Ag⁺ ion: Precipitate with NaCl. The adding of NaCl should produce a white precipitate.
Ag⁺(aq) + NaCl(s) → AgCl(s)↓ + Na⁺
For PO₄⁻³ ion: Precipitate with Ammonium Molybdate and Acid. This reaction should produce a yellow precipitate:
PO₄⁻³<span> + 3NH</span>₄⁺<span> + 12MoO</span>₄⁻²<span> + 24H</span>⁺<span> </span>→<span> (NH</span>₄)₃PO₄.12MoO₃(s)↓<span> + 12H</span>₂<span>O
</span>
Have a nice day!
The balanced reaction equation:
M(OH)2 ↔ M^2+ + 2(OH)^-
and when the Ksp = [M^2+][OH-]^2
when PH + POH = 14
∴ POH = 14-10.3= 3.7
and when POH = - ㏒ [OH-]
3.7 = -㏒[OH-]
∴[OH] = 2x10^-4
and when [M^2+] = 1/2[OH-]
∴[M^2+] = (2x10^-4) / 2 = 0.0001 M
So, by substitution in Ksp formula:
∴Ksp = (0.0001 * (2x10^-4)^2 = 4x10^-12
