1answer.
Ask question
Login Signup
Ask question
All categories
  • English
  • Mathematics
  • Social Studies
  • Business
  • History
  • Health
  • Geography
  • Biology
  • Physics
  • Chemistry
  • Computers and Technology
  • Arts
  • World Languages
  • Spanish
  • French
  • German
  • Advanced Placement (AP)
  • SAT
  • Medicine
  • Law
  • Engineering
Vladimir79 [104]
3 years ago
7

A flexible container at an initial volume of 6.13 L contains 6.51 mol of gas. More gas is then added to the container until it r

eaches a final volume of 18.3 L. Assuming the pressure and temperature of the gas remain constant, calculate the number of moles of gas added to the container.
Chemistry
1 answer:
aivan3 [116]3 years ago
6 0

Answer:

the final mole of the flexible container = 12.92 moles

Explanation:

Given that :

initial volume of a flexible container = 6.13 L

initial mole of a flexible container = 6.51 mol

final volume of a flexible container = 18.3 L

final mole of a flexible container = ???

Assuming the pressure and temperature of the gas remain constant, calculate the number of moles of gas added to the container.

Therefore,

n= \dfrac{V_2*n_1}{V_1}

n= \dfrac{18.3*6.51}{6.13}

n = 19.43

n=n_1+n_2

19.43 = 6.51 + n₂

n₂ = 19.43 - 6.51

n₂ = 12.92 moles

Thus; the final mole of the flexible container = 12.92 moles

You might be interested in
Formula for the elements if they were to bong together. <br><br> Iodine and Bromine
blondinia [14]

Answer:

I(Br)

Explanation:

You will be combining one iodine atom with one bromine atom.

7 0
2 years ago
Read 2 more answers
If 27.3% of a sample of silver-112 decays in 1.52 hours, what is the half-life (in hours to 3 decimal places)?
ICE Princess25 [194]

<u>Answer:</u> The half life of the sample of silver-112 is 3.303 hours.

<u>Explanation:</u>

All radioactive decay processes undergoes first order reaction.

To calculate the rate constant for first order reaction, we use the integrated rate law equation for first order, which is:

k=\frac{2.303}{t}\log \frac{[A_o]}{[A]}

where,

k = rate constant = ?

t = time taken = 1.52 hrs

[A_o] = Initial concentration of reactant = 100 g

[A] = Concentration of reactant left after time 't' = [100 - 27.3] = 72.7 g

Putting values in above equation, we get:

k=\frac{2.303}{1.52hrs}\log \frac{100}{72.7}\\\\k= 0.2098hr^{-1}

To calculate the half life period of first order reaction, we use the equation:

t_{1/2}=\frac{0.693}{k}

where,

t_{1/2} = half life period of first order reaction = ?

k = rate constant = 0.2098hr^{-1}

Putting values in above equation, we get:

t_{1/2}=\frac{0.693}{0.2098hr^{-1}}\\\\t_{1/2}=3.303hrs

Hence, the half life of the sample of silver-112 is 3.303 hours.

6 0
3 years ago
What is dual behaviour of matter​
Andrej [43]

Answer:

Dual nature of matter is an important concept in JEE physics and is basically the study of different nature that a matter possesses or exhibits. ... Hence, the matter is said to possess dual nature, i.e., it has both the properties of a particle and as well as a wave.

4 0
3 years ago
Which of the following statements BEST explains dissolution?
nordsb [41]
I had the same question, it's most likely B.
5 0
3 years ago
Be sure to answer all parts. for each reaction, find the value of δso. report the value with the appropriate sign. (a) 3 no2(g)
Maurinko [17]

Answer:

Change in entropy for the reaction is

ΔS° = -268.13 J/K.mol

Explanation:

To calculate the change in entropy for the balanced reaction, we require the natural entropy of all the reactants and products in the reaction.

3 NO₂(g) + H₂O(l) → 2 HNO₃(l) + NO(g)

From Literature.

S°(NO₂) = 240.06 J/K.mol

S°(H₂O) = 69.91 J/K.mol

S°(HNO₃) = 155.60 J/K.mol

S°(NO) = 210.76 J/K.mol

These are the entropies of the reactants and products under standard conditions of 298.15 K and 1 atm.

Note that

ΔS° = Σ nᵢS°(for products) - Σ nᵢS°(for reactants)

Σ nᵢS°(for products) = [2 × S°(HNO₃)] + [1 × S°(NO)]

= (2 × 155.60) + (1 × 210.76) = 521.96 J/K.mol

Σ nᵢS°(for reactants) = [3 × S°(NO₂)] + [1 × S°(H₂O)]

= (3 × 240.06) + (1 × 69.91) =790.09 J/K.mol

ΔS° = Σ nᵢS°(for products) - Σ nᵢS°(for reactants)

ΔS° = 521.96 - 790.09 = -268.13 J/K.mol

Hope this Helps!!

4 0
3 years ago
Other questions:
  • What are the major products when glucose is broken down in glycolysis?
    13·1 answer
  • Type the correct answer in the box. Express the answer to two significant figures.
    5·2 answers
  • HELP PLEASE WILL GIVE BRAINLIEST ANSWER
    15·1 answer
  • Calcium and water form calcium hydroxide and hydrogen gas also called what type of reaction
    13·1 answer
  • How many moles are in 264 g of gold, Au?<br>1 point<br>​
    11·2 answers
  • Pressure drop in packed column ..... a tray column
    7·1 answer
  • A radical is a reactive intermediate with a single ___ electron, formed by ___ of a covalent bond. Allylic radicals are stabiliz
    5·1 answer
  • How many grams of na2co3 would be needed to produce 1000g of nahco3
    14·1 answer
  • Explain how astronomers use spectrographs to identify the composition of a star.
    6·1 answer
  • Why is burning fossil fuels a problem?
    15·2 answers
Add answer
Login
Not registered? Fast signup
Signup
Login Signup
Ask question!