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Vladimir79 [104]
4 years ago
7

A flexible container at an initial volume of 6.13 L contains 6.51 mol of gas. More gas is then added to the container until it r

eaches a final volume of 18.3 L. Assuming the pressure and temperature of the gas remain constant, calculate the number of moles of gas added to the container.
Chemistry
1 answer:
aivan3 [116]4 years ago
6 0

Answer:

the final mole of the flexible container = 12.92 moles

Explanation:

Given that :

initial volume of a flexible container = 6.13 L

initial mole of a flexible container = 6.51 mol

final volume of a flexible container = 18.3 L

final mole of a flexible container = ???

Assuming the pressure and temperature of the gas remain constant, calculate the number of moles of gas added to the container.

Therefore,

n= \dfrac{V_2*n_1}{V_1}

n= \dfrac{18.3*6.51}{6.13}

n = 19.43

n=n_1+n_2

19.43 = 6.51 + n₂

n₂ = 19.43 - 6.51

n₂ = 12.92 moles

Thus; the final mole of the flexible container = 12.92 moles

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QUESTION 3
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These questions are all about indirect and direct variation with PV=nRT, the ideal gas equation

Q3.
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Q5.
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Q6.
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refer to past question
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Q8
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Q9
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