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Taya2010 [7]
3 years ago
13

What is a quadrilateral with 1 pair of perpendicular sides?

Mathematics
2 answers:
algol [13]3 years ago
6 0
A trapezoid because it only has 1 pair.
ch4aika [34]3 years ago
5 0
A Trapeziod or a trapezum , depending on what country you live in.
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What is the radius and diameter of the following circle?
FromTheMoon [43]

Answer:

Radius = 16cm

Diameter = 32cm

Step-by-step explanation:

The Radius of a circle is half the diameter of the circle. The radius is how far the outside of the circle is from the middle of the circle. To find the Diameter add the radius twice, for example 16+16. Don’t forget your UNIT it is in Centimeters in this case.

7 0
3 years ago
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Find the area of the composite figure.
BARSIC [14]

Answer:

The total area is 132 ft squared

Step-by-step explanation:

I found the area of the triangle by doing bh/2 and got 60. I then found the read of the rectangle bu doing bh and got 72z I then added both areas and got 132 as the total area.

7 0
3 years ago
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PLZ ANSWER QUICK IT WILL HELP A LOT!
Ber [7]

Answer:

A

Step-by-step explanation:

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3 years ago
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The archway of the main entrance of a university is modeled by the quadratic equation
Scilla [17]

Answer:

B. (1,5) and (5.25, 3.94)

Step-by-step explanation:

The answer is where the 2 equations intersect.

We need to solve the following system of equations:

y = -x^2 + 6x

4y = 21 - x

From the second equation:

x = 21 - 4y

Plug this into the first equation:

y = -(21 - 4y)^2 + 6(21 - 4y)

y = -(441 - 168y + 16y^2)+  126 - 24y

y = -441 + 168y - 16y^2 +  126 - 24y

16y^2 + y - 168y + 24y + 441 - 126 = 0

16y^2 - 143y + 315 = 0

y = [-(-143) +/- sqrt ((-143)^2 - 4 * 16 * 315)]/ (2*16)

y = 5, 3.938

When y = 5:

x = 21 - 4(5) = 1

When y = 3.938

x = 21 - 4(3.938) = 5.25.

3 0
3 years ago
What is the answer to this ? PLEASE HELP I HAVE 3 minutes
inn [45]

Answer:

(2, 4)

General Formulas and Concepts:

<u>Pre-Algebra</u>

Order of Operations: BPEMDAS

  1. Brackets
  2. Parenthesis
  3. Exponents
  4. Multiplication
  5. Division
  6. Addition
  7. Subtraction
  • Left to Right

Equality Properties

  • Multiplication Property of Equality
  • Division Property of Equality
  • Addition Property of Equality
  • Subtract Property of Equality

<u>Algebra I</u>

  • Solving systems of equations using substitution/elimination

Step-by-step explanation:

<u>Step 1: Define Systems</u>

y = 2x

x = -y + 6

<u>Step 2: Solve for </u><em><u>y</u></em>

<em>Substitution</em>

  1. Substitute in <em>x</em>:                     y = 2(-y + 6)
  2. Distribute 2:                         y = -2y + 12
  3. Isolate <em>y</em> terms:                    3y = 12
  4. Isolate <em>y</em>:                               y = 4

<u>Step 3: Solve for </u><em><u>x</u></em>

  1. Define equation:                    x = -y + 6
  2. Substitute in <em>y</em>:                       x = -4 + 6
  3. Add:                                        x = 2
3 0
3 years ago
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