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saveliy_v [14]
3 years ago
15

determine which sequence is an arithmatic sequence. a. -10, 5, - 5/2, 5/4,... b. 1/5, 1/7, 1/9, 1/11, ... c. 3,6, 12, 24,... d.

-7, -3, 1, 5,...​
Mathematics
1 answer:
Damm [24]3 years ago
5 0

Answer:

d

Step-by-step explanation:

An arithmetic sequence has a common difference between its terms. The only sequence with a common difference is choice d, which has a common difference of -4. The other options have common ratios, making them geometric, not arithmetic, sequences.

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Sveta_85 [38]

Answer:

63.15% upcharge

Step-by-step explanation:

4 0
3 years ago
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The French club is sponsoring a bake sale to raise at least $365. How many pastries must they sell at $2.80
gregori [183]

Answer:

  • D. At least 131

Step-by-step explanation:

Let the number of pastries  is x.

<u>We have an inequality:</u>

  • 2.80x ≥ 365
  • x ≥ 365/2.80
  • x ≥ 130.357

The least whole number for x is 131.

Correct choice is D

7 0
2 years ago
A smog alert has been called in a certain area of Los Angeles County in which there are 50 industrial rms. An inspector will vis
damaskus [11]

Answer:

Part (A) The required PMF is: P(X=x)=\frac{\binom{15}{x}\binom{50-15}{10-x}}{\binom{50}{10}}

Part (B) B(x;n,p)=\binom{10}{x}(0.3)^x(1-0.3)^{10-x}

Step-by-step explanation:

Consider the provided information.

There are 50 industrial rms. An inspector will visit 10 randomly selected rms to check for violations of regulations.

Part (A)

15 of the rms are actually violating at least one regulation.

Let X is the number of firms violate at least one regulation from 10 randomly selected rms to check for violations of regulations out of 50 firms of which 15 5 of the rms are actually violating.

Therefore, X\sim Hypergeom(n=10, M=15\ and\ N=50)

We need to determine probability mass function.

P(X=x)=Hyper(x; n=10, M=15, N=50)\\=\frac{\binom{15}{x}\binom{50-15}{10-x}}{\binom{50}{10}}

Hence, the required PMF is: P(X=x)=\frac{\binom{15}{x}\binom{50-15}{10-x}}{\binom{50}{10}}

Part (B)  If there are 500 rms in the area, of which 150 are in violation, approximate the pmf of part.

Here N=500 so find the probability of p as shown below:

p=\frac{150}{500} =0.3 and n=10

B(x;n,p)=B(x;10,0.3)\\=\binom{10}{x}(0.3)^x(1-0.3)^{10-x}

5 0
4 years ago
3. Find the domain and range of the function represented by the graph.
maks197457 [2]
The range is 1 to -3 (both included) and the domain is -3 to 2 (both included)
4 0
1 year ago
I dont get it- pls help
Anettt [7]

Answer:

w

_ +3

2

Step-by-step explanation:

this should be the answer

6 0
3 years ago
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