<u>ANSWER: </u>
Fare of adult tickets is $13 and fare of child tickets is $5.
<u>SOLUTION: </u>
Given, Elisa school is selling tickets to the annual talent show.
Let, adult ticket fare be x and child ticket fare be y.
On the first day of ticket sales the school sold 8 adult tickets and 3 children tickets for a total of $119.
Then, 8x + 3y = 119 --- (1)
The school took in $135 on the second day by selling 10 adult tickets and 1 child ticket.
Then, 10x + y = 135
y = 135 – 10x ---- (2)
Now, substitute y value in (1)
8x + 3(135 – 10x) = 119
8x + 3 × 135 – 3 × 10x = 119
8x + 405 – 30x = 119
405 – 119 = 30x – 8x
286 = 22x
x =
x = 13
Now, substitute x value in (2)
y = 135 – 10(13)
y = 135 – 130 = 5
Hence, fare of adult tickets is $13 and fare of child tickets is $5.