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3 years ago

Find the rate of change in table plsss helppp!!!!

Mathematics

2 answers:

Iteru [2.4K]3 years ago

7 0

Answer:

.25 is the answer

Step-by-step explanation:

.5/2=.25

KonstantinChe [14]3 years ago

5 0

Answer:

it changes by 4

Step-by-step explanation:

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What is the answer to this <br>u(2u+5)-4(U+3)

Yakvenalex [24]

Answer:

its 2u^2-4u+5u-12

Step-by-step explanation:

7 0

3 years ago

If varies inversely as . It is known that = 10 when = 3, find the value of when = 5.

Leto [7]

Answer:

y = 6

Step-by-step explanation:

If x varies inversely proportional as y.

$x=\dfrac{k}{y}$ , k is constant of proportionality

k = xy

When x = 3 and y = 10

k = 3×10

k = 30

Put x = 5,

$y=\dfrac{k}{x}\\\\y=\dfrac{30}{5}\\\\y=6$

So, the value of y is 6 when x is 5.

8 0

2 years ago

Forces of 9 lbs and 13 lbs act at a 38º angle to each other. Find the magnitude of the resultant force and the angle that the re

fiasKO [112]

Answer: $R=20.84\ lb\quad 22.57^{\circ},15.43^{\circ}$

Step-by-step explanation:

Given

Two forces of 9 and 13 lbs acts $38^{\circ}$ angle to each other

The resultant of the two forces is given by

$\Rightarrow R=\sqrt{a^2+b^2+2ab\cos \theta}$

Insert the values

$\Rightarrow R=\sqrt{9^2+13^2+2(9)(13)\cos 38^{\circ}}\\\Rightarrow R=\sqrt{81+169+184.394}\\\Rightarrow R=\sqrt{434.394}\\\Rightarrow R=20.84\ lb$

Resultant makes an angle of

$\Rightarrow \alpha=\tan^{-1}\left( \dfrac{b\sin \theta}{a+b\cos \theta}\right)\\\\\text{Considering 9 lb force along the x-axis}\\\\\Rightarrow \alpha =\tan^{-1}\left( \dfrac{13\sin 38^{\circ}}{9+13\cos 38^{\circ}}\right)\\\\\Rightarrow \alpha =\tan^{-1}(\dfrac{8}{19.244})\\\\\Rightarrow \alpha=22.57^{\circ}$