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BaLLatris [955]
3 years ago
8

A water tank is being drained at a steady rate. The initial level of the water in the tank was 5.5 feet. The graph below shows t

he water level over time as the tank is drained

Mathematics
2 answers:
alisha [4.7K]3 years ago
5 0
The answer would be C. to find this use the rise over run method

dalvyx [7]3 years ago
5 0
The correct answer is C
Hope this helped :)
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The width of a rectangle is 4x-4 feet and the length is 2x+5 feet. Find the perimeter
Ipatiy [6.2K]
Perimeter is
2 • width+ 2•length=
2• (4x-4)+2•(2x+5)=
Distribute multiplication in parentheses
8x-8+4x+10=
Combine like terms
12x+2
4 0
3 years ago
What is the distance between the points 1 - 6 + -5 2
Nata [24]
(1, -6) and (-5, 2)

Distance between 1 and -5 = 6
Distance between -6 and 2 = 8

6²+8²=x² (PYTHAGOREAN THEOREM)
36+64=x²
x² = 100
x = 10

Note: Not -10 because <em>distance cannot be negative.</em>
5 0
3 years ago
If m∠XWY = 20°, m∠XWZ = 40°, and XY = 16, what is the value of YZ?
Jobisdone [24]
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7 0
3 years ago
For every 1% increase in
givi [52]

Answer:

The GDP gap is 9 % when there is 4.5 % unemployment.

Step-by-step explanation:

The statement shows a reverse relationship, where an increase in unemployment is following by decrease in potential GDP and can be translated into the following rate:

r = \frac{2\,\% \,GDP}{1\,\% unemp.}

The GDP gap at a given increase in unemployment can be estimated by the following expression:

\frac{g}{u} = r

g = r\cdot u

Where:

r - GDP gap-unemployment increase rate, dimensionless.

u - Increase in unemployment rate, measured in percentage.

g - GDP gap, measured in percentage.

If r = \frac{2\,\% \,GDP}{1\,\% unemp.} and u = 4.5\,\%\,unemp., the GDP gap is:

g = \left(\frac{2\,\%\,GDP}{1\,\%\,unemp.} \right)\cdot (4.5\,\%\,unemp.)

g = 9\,\%\,GDP

The GDP gap is 9 % when there is 4.5 % unemployment.

3 0
4 years ago
How did he get this 1/2i ? I dont remember studying this definition in calc 1 neither calc 2!
Hitman42 [59]
The i in the denominator is missing in the second expression. It should be

\sin at=\dfrac{e^{iat}-e^{-iat}}{2i}

This follows from

e^{iat}=\cos at+i\sin at
e^{-iat}=\cos at-i\sin at
\implies e^{iat}-e^{-iat}=2i\sin at
\implies \sin at=\dfrac{e^{iat}-e^{-iat}}{2i}
8 0
3 years ago
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