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attashe74 [19]
4 years ago
15

How are neutral atoms converted into anions?

Physics
1 answer:
Vladimir [108]4 years ago
7 0
Anion is negative ion.
In an atom, there is equal number of protons and electrons, thus the positive charges balanced out the negative charges so an atom have no charge.

To form a ion, you must understand that only electrons in an atom are allowed to move, protons cannot move before it is held in the nucleus by strong attraction force.
Thus, to form a anion, the atom have to gain electrons. So that the ion have more electrons than protons and hence becomes negatively charged.

Extra:
Similarly, to form a cation (positive ion), an atom have to lose electrons so that the ion have more protons than electrons and hence positively charged.
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Which process allows green plants to control the amount of water stored in their leaves
OleMash [197]
Transpiration is the what the process is called.
It controls the release of water through the stomata.
5 0
4 years ago
Which of the following is not a physical property of mattera. melting pointb.heat of combustionc. viscosityd. boiling point
NNADVOKAT [17]

Answer:

The Correct Answer is Heat of Combustion  

Explanation:

6 0
3 years ago
Vectors A and B lie in the xy ‑plane. Vector A has a magnitude of 17.1 and is at an angle of 150.5∘ counterclockwise from the +x
IRINA_888 [86]

Answer:

A = -14.87 i ^ + 8.42 j ^ + 0 k ^

B = -25.41 i ^ -12.0 j ^ + 0 k ^

Explanation:

For this exercise let's use trigonometry by decomposing to vectors

vector A

module 17.1 with an angle of 150.5 counterclockwise.

         Sin 150.5 = A_{y} / A

         cos 150.5 = Ax / A

         A_{y} = A sin 150.5 = 17.1 sin 150.5

         Aₓ = A cos 1505 = 172 cos 150.5

         A_{y} = 8,420

         Aₓ = -14.870

the vector is

          A = -14.87 i ^ + 8.42 j ^ + 0 k ^

Vector B

         B_{y} = 28.1 sin 205.3

         Bₓ = 28.1 cos 205.3

         B_{y} = -12.009

          Bₓ = -25.405

the vector is

          B = -25.41 i ^ -12.0 j ^ + 0 k ^

5 0
3 years ago
Kraig pulls a box to the right at an angle of 40 degrees to the horizontal with a force of 30 Newtons. If Kraig pulls the box a
eimsori [14]

Answer:

459.6J

Explanation:

Given parameters:

Angle of pull  = 40°

Force applied  = 30N

Distance moved = 20m

Unknown:

Work done by Kraig  = ?

Solution:

To solve this problem;

   Work done  = F x dcosФ

d is the distance

F is the force

Ф is the angle given

  Work done  = 30 x 20cos40°   = 459.6J

3 0
3 years ago
Chapter 05, Problem 15 Multiple-Concept Example 7 and Concept Simulation 5.2 review the concepts that play a role in this proble
Llana [10]

Answer:

Explanation:

The question relates to motion on a circular path .

Let the radius of the circular path be R .

The centripetal force for circular motion is provided by frictional force

frictional force is equal to μmg , where μ is coefficient of friction and mg is weight

Equating cenrtipetal force and frictionl force in the case of car A

mv² / R = μmg

R = v² /μg

= 26.8 x 26.8 / .335 x 9.8

= 218.77 m

In case of moton of car B

mv² / R = μmg

v²  = μRg

= .683  x 218.77x 9.8

= 1464.35

v = 38.26 m /s .

3 0
3 years ago
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