1answer.
Ask question
Login Signup
Ask question
All categories
  • English
  • Mathematics
  • Social Studies
  • Business
  • History
  • Health
  • Geography
  • Biology
  • Physics
  • Chemistry
  • Computers and Technology
  • Arts
  • World Languages
  • Spanish
  • French
  • German
  • Advanced Placement (AP)
  • SAT
  • Medicine
  • Law
  • Engineering
Anuta_ua [19.1K]
3 years ago
13

Find out the x-component and y-component of the following vectors:

Physics
2 answers:
Nina [5.8K]3 years ago
8 0
<h2>Answer:</h2><h2></h2>

The x- and y- components of vector A are -12.99cm and 7.5cm respectively.

The x- and y- components of vector B are 7.71m and 9.20m respectively.

The x- and y- components of vector C are -21.45m/s and -18.00m/s respectively.

The x- and y- components of vector D are 22.94m/s² and -16.06m/s² respectively.

<h2>Explanation:</h2><h2></h2>

Given an arbitrary vector M (written in bold face), of magnitude M (not written in bold face), which makes an angle θ to the positive x axis, the x-component of M (written as M_{X}) is given by;

M_{X} = M cos θ

And its y-component (written as M_{Y}) is given by;

M_{Y} = M sin θ

Therefore, taking due east as positive x axis, for the vector:

<em>(i) A = 15.0 cm; the vector is 30.00 north of west; </em>

the x-component of A (written as A_{X}) is given by;

A_{X} = A cos θ            --------------------(i)

And its y-component (written as A_{Y}) is given by;

A_{Y} = A sin θ              --------------------(ii)

<em>Where;</em>

A = 15.0cm

θ = 30.00 north of west =  180° - 30.00° [measured due east] = 150°

<em>Substitute these values into equations (i) and (ii) as follows;</em>

A_{X} = 15.0 cos 150° =  15.0 x -0.8660 = -12.99cm      

A_{Y} = 15.0 sin 150° = 15.0 x 0.5 = 7.5cm

Therefore, the x- and y- components of vector A are -12.99cm and 7.5cm respectively.

<em>(ii) B = 12.0 m; the vector is 55.00 north of east; </em>

the x-component of B (written as B_{X}) is given by;

B_{X} = B cos θ            --------------------(iii)

And its y-component (written as B_{Y}) is given by;

B_{Y} = B sin θ              --------------------(iv)

<em>Where;</em>

B = 12.0m

θ = 55.0 north of east =  50° [measured due east]

<em>Substitute these values into equations (iii) and (iv) as follows;</em>

B_{X} = 12.0 cos 50° =  12.0 x 0.6428 = 7.71m      

B_{Y} = 12.0 sin 50° = 12.0 x 0.7660 = 9.20m

Therefore, the x- and y- components of vector B are 7.71m and 9.20m respectively.

<em>(iii) C = 28.0 m/s; the vector is 40.00 south of west; </em>

the x-component of C (written as C_{X}) is given by;

C_{X} = B cos θ            --------------------(v)

And its y-component (written as C_{Y}) is given by;

C_{Y} = B sin θ              --------------------(vi)

<em>Where;</em>

C = 28.0m/s

θ = 40.00 south of west =  180° + 40.00° [measured due east] = 220°

<em>Substitute these values into equations (v) and (vi) as follows;</em>

C_{X} = 28.0 cos 220° =  28.0 x -0.7660 = -21.45m/s

C_{Y} = 28.0 sin 220° = 28.0 x -0.6428 = -18.00m/s

Therefore, the x- and y- components of vector C are -21.45m/s and -18.00m/s respectively.

<em>(iv) D = 55.5 m/s²; the vector is 35.00 south of east; </em>

the x-component of D (written as D_{X}) is given by;

D_{X} = D cos θ            --------------------(vii)

And its y-component (written as D_{Y}) is given by;

D_{Y} = D sin θ              --------------------(viii)

<em>Where;</em>

D = 55.5m/s²

θ = 35.00 south of east =  360° - 35.00° [measured due east] = 325°

<em>Substitute these values into equations (vii) and (viii) as follows;</em>

D_{X} = 55.5 cos 325° =  28.0 x 0.8192 = 22.94m/s²

D_{Y} = 55.5 sin 325° = 28.0 x -0.5736= -16.06m/s²

Therefore, the x- and y- components of vector D are 22.94m/s² and -16.06m/s² respectively.

Leno4ka [110]3 years ago
6 0

Answer:

A = 15.0 cm; the vector is 30.00 north of west; = 15 cm N30W

Y - component = 7.5cm and X - component = -12.99 cm

B = 12.0 m; the vector is 55.00 north of east; = 12.0 m N55E

Y - component = 9.83 m and X - component = 6.88 m

C = 28.0 m/s; the vector is 40.00 south of west; = 28.0 m/s S40W

Y - component =  - 17.998 m/s and X - component = - 21.448 m/s

D = 55.5 m/s2; the vector is 35.00 south of east; = 55.5 m/s² S35E

Y - component = - 31.835 m/s² and X - component  = 45.466 m/s²

Explanation:

1. A = 15.0 cm; the vector is 30.00 north of west; = 15 cm N30W

Y - component = 15cm × sin30 = 7.5cm

X - component = -15cm × cos30 = -12.99 cm

2. B = 12.0 m; the vector is 55.00 north of east; = 12.0 m N55E

Y - component = 12.0 m × sin55 = 9.83 m

X - component =12.0 m × cos55 = 6.88 m

3. C = 28.0 m/s; the vector is 40.00 south of west; = 28.0 m/s S40W

Y - component = - 28.0 m/s × sin40 = - 17.998 m/s

X - component =  - 28.0 m/s × cos40 = - 21.448 m/s

4. D = 55.5 m/s2; the vector is 35.00 south of east; = 55.5 m/s² S35E

Y - component = - 55.5 m/s² × sin35 = - 31.835 m/s²

X - component = 55.5 m/s² × cos35 = 45.466 m/s²

You might be interested in
A partical of an atom that carries a negative charge is called a a/n
jeka57 [31]
It is called a negative nuetron/atom
7 0
3 years ago
Read 2 more answers
How would you respond to a person who argued that the Big Bang theory is incorrect because it is only a theory and theories have
Umnica [9.8K]

Well, you would reply that that's not what theories are. Theories explain the how and the why, laws explain the what. So, the Big Bang theory isn't "just a theory". It's a theory, it explains the how. (Also, if someone tells you it's anti-God or whatever, tell them the thoery was created by a Catholic scientist. True fact.) I hoped this helped!!! (You don't have the include who created the theory if this is for homework.)

5 0
3 years ago
Read 2 more answers
In an electrolytic cell, to which electrode will a positive ion migrate and undergo reduction? the anode, which is negatively ch
ahrayia [7]
The reaction of reduction always undergoes with the cathode, the positive ion will migrate towards the cathode with the negative charge whilst the anode always has oxidation reaction. These two types of reaction does not change.
4 0
3 years ago
Read 2 more answers
a flashlight has a resistance of 2.4 ohms. what voltage is applied by the batteries if the current in the circuit is 2.5A?
Mashcka [7]

E = I R

That means 

        Voltage = (current) x (resistance)

                     =   (2.5 A)  x  (2.4 ohms)

                     =       6 volts .


8 0
3 years ago
Read 2 more answers
I lost 1 point on this and I don’t know what I did wrong.
Viktor [21]

Answer:

i think its because u gave the almost every answer the same exact thing. all the questions have different ways of moving which means different forces for each one i hope this helps :)

Explanation:

4 0
3 years ago
Read 2 more answers
Other questions:
  • Which type of mirror produces images that are always upright and at the same distance from the mirror as the object is?
    8·2 answers
  • Which of the following utilize electromagnetic induction to operate?   
    12·1 answer
  • An object in simple harmonic motion has an amplitude of 0.360 m and an oscillation period of 0.620 s. Determine the maximum spee
    14·1 answer
  • Rupert (66 kg) is now in a full-pipe of radius 25 m, calculate the minimum speed at which Rupert can skate to ensure he will not
    9·1 answer
  • A e B são dos blocos de massas 3,0 kg e 2,0 kg, respectivamente, que se movimentam juntos sobre uma superficie horizontal e perf
    14·1 answer
  • The force that opposes motion to moving parts is _____
    15·1 answer
  • Whats the mass of the sun times pi?
    13·1 answer
  • If a certain mass of mercury has a volume of 0.002 m3 at a temperature of 20°C, what will be the volume at 50°C?
    7·1 answer
  • the weatherman reports the storm waves are about 2 meters high and 35 meters apart. What properties of waves is the reporter des
    6·1 answer
  • A truck initially traveling at a speed of 22 m/s increases at a constant rate of 2.4 m/s^2 for 3.2s. What is the total distance
    12·1 answer
Add answer
Login
Not registered? Fast signup
Signup
Login Signup
Ask question!