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tankabanditka [31]
2 years ago
5

S Four identical particles, each having charge q and mass m, are released from rest at the vertices of a square of side L. How f

ast is each particle moving when their distance from the center of the square doubles?
Physics
1 answer:
SashulF [63]2 years ago
4 0

The charged particle will have velocity of 5.41 kq^2/ mL .

What is Kinetic energy ?

A particle or an item that is in motion has a sort of energy called kinetic energy. An item accumulates kinetic energy when work, which involves the transfer of energy, is done on it by exerting a net force.

Here electric potential will be :

Ui = 4k q^2 / L +2k q^2 / L root2

when we double the distance of charges the final potential is :

Uf = 2kq^2 /L + 2k Q^2/ L root2

Kinetic energy : Uf - Ui

so after putting the values and solving the equation we get :

v= 5.41 kq^2/ mL

To learn more about kinetic energy click on the link below:

brainly.com/question/12337396

#SPJ4

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