<u>Answer:</u>
The length of a paper clip chain is directly proportional to the number of paper clips. If a chain with 65 paper clips has a length of 97.5 inches then the length of chain with 14 paper clips is 21 inches.
<u>Solution:</u>
Given that the length of a paper clip chain is directly proportional to the number of paper clips. Directly propotional means when the length of paper clip increases, then the number of paper clips also increases in same ratio.
Hence, by above definition, we get
------- eqn 1
From question, for a chain with 65 paper clips has a length of 97.5 inches, we get
Similarly, for a chain with 14 paper clips with length to be found, we get
Now by using eqn 1, we can calculate the length of 14 paper clips is,
Rearranging the terms we get,
Hence the length of chain with 14 paper clips is 21 inches.
Answer:
49
Step-by-step explanation:
4^3=64
5(-3)=-15
64+(-15)=49
The steps for dividing fractions are:
Keep
Flip
Change
As in, keep the first fraction the same (we can write 7 as 7/1 to make it a fraction), flip the second fraction upside down, and then change the division symbol to a multiplication symbol. This gives you:
7/1 × 5/6
And to multiply fractions, you multiply across, which means that you do (7 × 5 = 35)/(1 × 6 = 6). Your answer, therefore, is 35/6, or, as a mixed number, 5 5/6. I hope this helps!
Speed = distance / time
Speed = 182.4 / 3
Speed = 60.8 miles per hour.
Answer:
1/16
Step-by-step explanation:
This question involves two distinct genes; one coding for seed shape and the other for cotyledon color. The alleles for round seeds (R) and yellow cotyledons (Y) are dominant over the alleles for wrinkled seed (r) and green cotyledon (y) respectively.
In a cross between a truebreeding (i.e. same alleles for both genes) pea having round seeds and yellow cotyledon (RRYY) and a truebreeding pea having wrinkled seeds and green cotyledon (rryy), the F1 offsprings will all possess a heterozygous round seed and yellow cotyledon (RrYy).
The F1 offsprings (RrYy) will produce the following gametes: RY, Ry, rY, and ry. Using these gametes in a punnet square (see attached image), 16 possible offsprings will be produced in a ratio 9:3:3:1.
According to the question, 3/16 of the F2 offsprings will possess round seeds and green cotyledons, however, only 1 of them will be truebreeding i.e. RRyy. Hence, 1/16 of the F2 offsprings will be truebreeding for round seeds and green cotyledons.
