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mylen [45]
2 years ago
7

X

Mathematics
1 answer:
Veseljchak [2.6K]2 years ago
3 0
Sorry fdont really no
You might be interested in
how do you find a percentage of a number. Provide an example. Well not a specific number put jow do i find it ?
ollegr [7]
To find a percentage, if I am ready your question correctly, would be as simple as dividing the number by 100. For example, finding the percentage of 73.

73/100 = .73%

You could also just move the decimal place over two spots to the left.
7 0
3 years ago
18n squared + 57n -10
aniked [119]
Most people use the decomposition method but i dont know how to do that so i use the Joes method a method similar to decomp. but easier.
canadian way

Find gcf: None
complet trinomial: 18n^2+57-10
find the product=10(18)
                       =-180
find the sum     =57
-3 and 60 goes into both meaning if you multiply 3 and60 you get -180 and if you add them you get 57.

so (n-3)(n+60)
divide by a in this case it 18
so (n<u>-3</u>)(n+<u>60</u>)
       18     18
do not divide. treat it like a fraction so you reduce it to lowest terms
(n<u>-3</u>)(n<u>-3)
</u>   18   10
<u /> at this point its reduced to lowest terms so now you take the deniminator and move it beside the "n"

=(18n-3)(10n-3)

therefore your answer is (18n-3)(10n-3)
I hoped this helped :)
3 0
3 years ago
I need help please with this
lord [1]

Answer:

no.

Step-by-step explanation:

nigerians are cool

6 0
3 years ago
Can someone help me with this
Alexxandr [17]

Answer:

B

Step-by-step explanation:

the perimeter (P) of a rectangle is calculated as

P = 2l + 2w ( l is the length and w the width ) , then

P = 2(3\sqrt{15} ) + 2(\sqrt{15} ) ← distribute both parenthesis )

   = 6\sqrt{15} + 2\sqrt{15}

   = 8\sqrt{15}

5 0
2 years ago
Three cards are drawn from a standard deck of 52 cards without replacement. Find the probability that the first card is an ace,
MrRissso [65]

Answer:

4.82\cdot 10^{-4}

Step-by-step explanation:

In a deck of cart, we have:

a = 4 (aces)

t = 4 (three)

j = 4 (jacks)

And the total number of cards in the deck is

n = 52

So, the probability of drawing an ace as first cart is:

p(a)=\frac{a}{n}=\frac{4}{52}=\frac{1}{13}=0.0769

At the second drawing, the ace is not replaced within the deck. So the number of cards left in the deck is

n-1=51

Therefore, the probability of drawing a three at the 2nd draw is

p(t)=\frac{t}{n-1}=\frac{4}{51}=0.0784

Then, at the third draw, the previous 2 cards are not replaced, so there are now

n-2=50

cards in the deck. So, the probability of drawing a jack is

p(j)=\frac{j}{n-2}=\frac{4}{50}=0.08

Therefore, the total probability of drawing an ace, a three and then a jack is:

p(atj)=p(a)\cdot p(j) \cdot p(t)=0.0769\cdot 0.0784 \cdot 0.08 =4.82\cdot 10^{-4}

4 0
3 years ago
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