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patriot [66]
3 years ago
7

A motorcycle has a constant acceleration of 2.5 m/s2 . Both the velocity and acceleration of the motorcycle point in the same di

rection. How much time is required for the motorcycle to change its speed from (a) 21 to 31 m/s, and (b) 51 to 61 m/s?
Physics
1 answer:
Vera_Pavlovna [14]3 years ago
6 0

Answer:

4 seconds both, due to constant acceleration.

Explanation:

Acceleration is speed change over time as magnitude, then for a) a=(31-21)m/s  / t, then we can calculate t as (31-21)m/s  / a = (31-21)m/s  / 2,5 m/s^2 = 4 seconds. b) a=(61-31)m/s  / t, again t=(61-51)m/s  / a=(61-51)m/s  / 2,5 m/s^2 = 4 seconds.

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No.

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Random errors can result from the instrument not being precise or from mistakes by the researcher.

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Answer:

M' = μ₀n₁n₂πr₂²

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So, M = N₂Ф₂₁/i₁

substituting the values of the variables into the equation, we have

M = N₂Ф₂₁/i₁

M = N₂B₁A₂/i₁

M = n₂lμ₀n₁i₁πr₂²/i₁

M = lμ₀n₁n₂πr₂²

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M' = μ₀n₁n₂πr₂²

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