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patriot [66]
3 years ago
7

A motorcycle has a constant acceleration of 2.5 m/s2 . Both the velocity and acceleration of the motorcycle point in the same di

rection. How much time is required for the motorcycle to change its speed from (a) 21 to 31 m/s, and (b) 51 to 61 m/s?
Physics
1 answer:
Vera_Pavlovna [14]3 years ago
6 0

Answer:

4 seconds both, due to constant acceleration.

Explanation:

Acceleration is speed change over time as magnitude, then for a) a=(31-21)m/s  / t, then we can calculate t as (31-21)m/s  / a = (31-21)m/s  / 2,5 m/s^2 = 4 seconds. b) a=(61-31)m/s  / t, again t=(61-51)m/s  / a=(61-51)m/s  / 2,5 m/s^2 = 4 seconds.

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when an object is placed near a concave mirror, at what position does it forms a magnified and erect image.​
alexira [117]

Answer:

Between the principal focus and the pole of the mirror

4 0
3 years ago
The spring is unstretched at the position x = 0. under the action of a force p, the cart moves from the initial position x1 = -8
hammer [34]
Missing figure and missing details can be found here:
<span>http://d2vlcm61l7u1fs.cloudfront.net/media%2Fdd5%2Fdd5b98eb-b147-41c4-b2c8-ab75a78baf37%2FphpEgdSbC....
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Solution:
(a) The work done by the spring is given by
W= \frac{1}{2} k (\Delta x)^2 &#10;
where k is the elastic constant of the spring and \Delta x is the stretch between the initial and final position. Since x1=-8 in=-0.203 m and x2=5 in=0.127 m, we have
W= \frac{1}{2} \cdot 500 N/m \cdot (0.127m-(-0.203m))^2=27.25 J

(b) The work done by the weight is the product of the component of the weight parallel to the inclined plane and the displacement of the cart:
W_W = -F_{//} (x_2 -x_1)
where  the negative sign is given by the fact that F_{//} points in the opposite direction of the displacement of the cart, and where
F_{//}=m g sin 15^{\circ}=6 kg \cdot 9.81m/s^2 \cdot sin 15^{\circ}=15.2 N
therefore, the work done by the weight is
W_W=-15.2 N \cdot (0.203m-(-0.127m))=-5.02 J

8 0
3 years ago
While playing baseball with your friends your hands begin to sting after you ctach several fast balls.
muminat

Answer:

Explanation:

To stop a ball with high momentum in a small-time imparts a high amount of impact on hands. This is the reason for the stinging of hands.

The momentum of the ball is due to the mass and velocity. To prevent stinging in the hand one needs to lower his hands to increase the time of contact. In this way, the momentum transfer to the hands will be lesser.        

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Soloha48 [4]
I think it’s C b/c it works for me
3 0
3 years ago
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Alla [95]

Answer:

house wouldn't have solid walls on all four sides. Instead, some of the wall areas would be replaced by substances that

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drawbacks might there be to this design?

Explanation:

3 0
3 years ago
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