1answer.
Ask question
Login Signup
Ask question
All categories
  • English
  • Mathematics
  • Social Studies
  • Business
  • History
  • Health
  • Geography
  • Biology
  • Physics
  • Chemistry
  • Computers and Technology
  • Arts
  • World Languages
  • Spanish
  • French
  • German
  • Advanced Placement (AP)
  • SAT
  • Medicine
  • Law
  • Engineering
patriot [66]
3 years ago
7

A motorcycle has a constant acceleration of 2.5 m/s2 . Both the velocity and acceleration of the motorcycle point in the same di

rection. How much time is required for the motorcycle to change its speed from (a) 21 to 31 m/s, and (b) 51 to 61 m/s?
Physics
1 answer:
Vera_Pavlovna [14]3 years ago
6 0

Answer:

4 seconds both, due to constant acceleration.

Explanation:

Acceleration is speed change over time as magnitude, then for a) a=(31-21)m/s  / t, then we can calculate t as (31-21)m/s  / a = (31-21)m/s  / 2,5 m/s^2 = 4 seconds. b) a=(61-31)m/s  / t, again t=(61-51)m/s  / a=(61-51)m/s  / 2,5 m/s^2 = 4 seconds.

You might be interested in
Whats the texture of copper wire​
bixtya [17]

Copper is a reddish orange, soft metal with a bright metallic luster. It is an excellent conductor of heat and electricity. Copper surfaces when exposed to air gradually turns to a dull, brownish color.

8 0
3 years ago
In the simulation above, as the projectile travels upward, how does the vertical velocity change? Question 9 options:
enot [183]

Answer:

Vertical velocity decreases.

Explanation:

The motion of the ball is a projectile ball, which consists of two independent motions:

- a horizontal motion, with constant velocity

- a vertical motion, with constant acceleration g=9.8 m/s^2 towards the ground

In the vertical motion, there is a constant acceleration directed downward: this means that the vertical velocity decreases as the ball goes higher. In fact, it decreases following the equation

v(t)=v_0 -gt

And it decreases until the ball reaches its maximum height, then it starts increasing again.

4 0
4 years ago
How many known planets are in our galaxy?
strojnjashka [21]
There are 100 billion planets
8 0
3 years ago
A ball with 100 J of PE is released from a height of 10 m. What will be the KE of the ball at 5
harkovskaia [24]

Answer:

The kinetic energy is: 50[J]

Explanation:

The ball is having a potential energy of 100 [J], therefore

PE = [J]

The elevation is 10 [m], and at this point the ball is having only potential energy, the kinetic energy is zero.

E_{p} =m*g*h\\where:\\g= gravity[m/s^{2} ]\\m = mass [kg]\\m= \frac{E_{p} }{g*h}\\ m= \frac{100}{9.81*10}\\\\m= 1.01[kg]\\\\

In the moment when the ball starts to fall, it will lose potential energy and the potential energy will be transforme in kinetic energy.

When the elevation is 5 [m], we have a potential energy of

P_{e} =m*g*h\\P_{e} =1.01*9.81*5\\\\P_{e} = 50 [J]\\

This energy is equal to the kinetic energy, therefore

Ke= 50 [J]

8 0
3 years ago
You tie a cord to a pail of water and swing the pail in a vertical circle of radius 0.710 mm . What minumum speed must the pail
Blababa [14]

Answer:

The minumum speed the pail must have at its highest point if no water is to spill from it

= 2.64 m/s

Explanation:

Working with the forces acting on the water in the pail at any point.

The weight of water is always directed downwards.

The normal force exerted on the water by the pail is always directed towards the centre of the circle of the circular motion.

And the centripetal force, which keeps the system in its circular motion, is the net force as a result of those two previously mentioned force.

At the highest point of the motion, the top of the vertical circle, the weight and the normal force on the water are both directed downwards.

Net force = W + (normal force)

But the speed of this motion can be lowered enough to a point where the normal force becomes zero at the moment the pail reaches the highest point of its motion. Any speed lower than this value would result in the water spilling out of the pail. The water would not be able to resist the force of gravity.

At this point of minimum velocity,

Normal force = 0

Net force = W

Net force = centripetal force = (mv²/r)

W = mg

(mv²/r) = mg

r = 0.710 m

g = 9.8 m/s²

v² = gr = 9.8 × 0.71 = 6.958

v = √(6.958) = 2.64 m/s

Hope this Helps!!!

7 0
3 years ago
Other questions:
  • Is Newton's third law of motion relevant to dropping an egg
    13·1 answer
  • A model rocket is launched straight upward with an initial speed of 50.6 m/s. It accelerates with a constant upward acceleration
    15·1 answer
  • Which of the following actions is best understood using Einstein's concepts rather than Newtonian physics?
    10·2 answers
  • A water skier is pulled behind a boat. When the skis push down on the water, what is the reaction force?
    5·2 answers
  • Which type of electromagnetic wave has the longest wavelength
    8·1 answer
  • You are designing a hydraulic lift for a machine shop. The average mass of a car it needs to lift is about 1500 kg. You wish to
    6·1 answer
  • A net force of 15 N is exerted on an encyclopedia to cause it to accelerate at a rate of 5m/s/s. Determine the mass of the encyc
    15·1 answer
  • A gorilla drags a log across the jungle floor. The log begins at rest and accelerates at until the gorilla is moving at a fast l
    15·1 answer
  • PLEASE HELP!!!!!!
    9·1 answer
  • Nancy ran a distance of 5km in 30 minutes. What is her speed in meters(m) per hour)h)
    7·1 answer
Add answer
Login
Not registered? Fast signup
Signup
Login Signup
Ask question!