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Radda [10]
3 years ago
13

when an object is placed near a concave mirror, at what position does it forms a magnified and erect image.​

Physics
1 answer:
alexira [117]3 years ago
4 0

Answer:

Between the principal focus and the pole of the mirror

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A 3.4kg aluminium ball has an apparent mass of 2.10kg when submerged in a particular liquid. Calculate the density of the liquid
Shalnov [3]

Answer:

1083.3kg/m ³

Explanation:

Given parameters:

Mass of aluminium ball = 3.4kg

Apparent mass of ball = 2.1kg

Unknown:

Density of the liquid = ?

Solution:

Density is is the mass per unit volume of any give substance;

         Density = \frac{mass}{volume}

     Now, we must understand that the apparent weight of the aluminium is the part of its weight supported by the fluid;

     

   Pl = \frac{Ml}{Vl}

   Pl = density of liquid

   Ml = mass of liquid

   Vl = volume of liquid

 Mass of liquid = Mal - Mapparent

       Mal = mass of aluminium

The volume of liquid displaced is the same as the volume of the aluminium according to Archimedes's principle;

              Ml = Pl x Vl

      Val = Vl

      Val volume of aluminium

      Vl = volume of liquid

            ****

        Pal = \frac{Mal}{Val}

       Val = \frac{Mal}{Pal}

       Val = volume of aluminium

       Mal = mass of aluminium

       Pal = density of aluminium

   *****

      Since the Val = Vl

          Ml = Pl x \frac{Mal}{Pal}

    Since

          Ml = Mal - Mapparent

                Mal - Mapparent  = Pl  x \frac{Mal}{Pal}

Pal = density of aluminium = 2712 kg/m ³

             3.4 - 2.1 = Pl x \frac{3.4}{2712}

                 1.3 = Pl x 0.00123

                    Pl = 1083.3kg/m ³

       

5 0
3 years ago
Which component of magma includes mobile ions of silicon?
Lemur [1.5K]

Answer:

Melt.

Explanation:

When rocks melt, they do so slowly and gradually because most rocks are made of several minerals, which all have different melting points; moreover, the physical and chemical relationships controlling the melting are complex. As a rock melts, for example, its volume changes. When enough rock is melted, the small globules of melt link up and soften the rock.

Under normal conditions, mantle rock like peridotite shouldn't melt in the Earth's upper mantle. However, by adding water you can lower the melting point of the rock. Alternatively, by decompressing the rock, you can bring it to a pressure where the melting point is lower. In both cases, basalt magma will form and considering it is hotter and less dense than the surrounding rock, it will percolate towards the surface and some of that erupts.

6 0
3 years ago
One form of energy can be _____ another type of energy.
kotegsom [21]

We can answer this one very quickly.  From the <em>Law of Conservation of Energy</em>, we know that "Energy can't be created or destroyed.".

So that only leaves us one way to complete the sentence in this question:

"One form of energy can be <em>transformed into</em> another type of energy. "  <em>(B)</em>

4 0
3 years ago
A horse 1 m tall running towards a tree at a constant velocity of 20m/s,
kykrilka [37]

The horse's position on the ground at time <em>t</em> is

<em>x</em> = (20 m/s) <em>t</em>

The baboon's height from the ground at time <em>t</em> is

<em>y</em> = 3 m - 1/2 <em>g</em> <em>t</em>²

where <em>g</em> = 9.80 m/s² is the magnitude of the acceleration due to gravity.

The baboon falls and lands on the horse, so that the two animals meet when the baboon's height is 2 m from the ground, which happens after

2 m = 3 m - 1/2 <em>g</em> <em>t</em>²

1/2 <em>g</em> <em>t</em>² = 1 m

<em>t</em>² = (2 m) / (9.80 m/s²)

<em>t</em> ≈ 0.452 s

In this time, the horse reaches the tree, so its distance from it is

(20 m/s) * (0.452 s) ≈ 9.04 m

7 0
4 years ago
A lead fishing weight of mass 0.20 kg is tied to a fishing line that is 0.50 m long. The weight is then whirled in a vertical ci
solong [7]

Answer:

Following are the solution to this question

Explanation:

please find the complete question in the attached file.

In point a:

The answer is "bottom".

In point b:

Using formula:

T= mg + \frac{m V^2}{2}

\to 100= 0.2 \times 9.81 + \frac{0.2 \times V^2}{0.5}

\to 100= 1.962+ \frac{0.2 + V^2}{0.5}\\\\\to  100- 1.962= \frac{0.2 + V^2}{0.5}\\\\\to  98.038= \frac{0.2 + V^2}{0.5}\\\\\to  49.019=0.2+V^2\\\\\to  48.819=V^2\\\\ \to  6.987 \ \frac{m}{s}

6 0
3 years ago
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