Answer:

Explanation:
In this process energy must be conserved. On the initial stage, there will be only gravitational potential energy, while on the final stage there will be only elastic potential energy, so they will be equal. We write this as:

Which is the same as:

So we can obtain our mass from there, and for our values:

Answer:

Explanation:
<u>Horizontal Launch
</u>
It happens when an object is launched with an angle of zero respect to the horizontal reference. It's characteristics are:
- The horizontal speed is constant and equal to the initial speed

- The vertical speed is zero at launch time, but increases as the object starts to fall
- The height of the object gradually decreases until it hits the ground
- The horizontal distance where the object lands is called the range
We have the following formulas




Where
is the initial horizontal speed,
is the vertical speed, t is the time, g is the acceleration of gravity, x is the horizontal distance, and y is the height.
If we know the initial height of the object, we can compute the time it takes to hit the ground by using

Rearranging and solving for t



We then replace this value in

To get



The initial speed depends on the initial height y=32.5 m, the range x=107.6 m and g=9.8 m/s^2. Computing 

The launch velocity is

C. Because they are in the same group, so they have the same number of valence (outer) electrons
Radiative power scales with the fourth power of temperature, so 160 W.