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3 years ago

9

A 80-cm-wide object seen through an optical device appears inverted and 50 cm wide. What is the magnification of the optical dev

ice?
A. 1.3
B. 0.63
C. -0.63
D. 2.5
E. -1.3

1 answer:

Arte-miy333 [17]3 years ago

6 0

The magnification is the ratio between the size of the image $h_i$ and the size of the original object $h_o$ :
$M= \frac{h_i}{h_o}$
The sign of the magnification contains another piece of information: if it's positive, then the image is upright, if it's negative, the image is inverted. In our problem, the image is inverted, so the magnification will have a negative sign, and it will be
$M=(-) \frac{50 cm}{80 cm}=-0.63$

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L = 0.75 m is the its length

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Answer : The magnitude of the lattice energy for CsCl is, 667 KJ/mole

Explanation :

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