A 80-cm-wide object seen through an optical device appears inverted and 50 cm wide. What is the magnification of the optical dev
1 answer:
The magnification is the ratio between the size of the image 
and the size of the original object 
:
The sign of the magnification contains another piece of information: if it's positive, then the image is upright, if it's negative, the image is inverted. In our problem, the image is inverted, so the magnification will have a negative sign, and it will be
The sign of the magnification contains another piece of information: if it's positive, then the image is upright, if it's negative, the image is inverted. In our problem, the image is inverted, so the magnification will have a negative sign, and it will be
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Answer:
0.113097335529 Nm
Explanation:
t = Time taken
u = Initial velocity
v = Final velocity
a = Acceleration
I = Moment of inertia = 0.3 kgm²
Torque is given by
The magnitude of torque is 0.113097335529 Nm
Answer:
Fundamental frequency is 200 Hz.
Explanation:
It is given that,
Frequency of the 3rd harmonic is 600 Hz.
Let f is the fundamental frequency. We need to find the value of f. The frequency of third harmonic is given by :
So, fundamental frequency f is equal to :
f = 200 Hz
So, the fundamental frequency of the harmonics is 200 Hz. Hence, this is the required solution.