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murzikaleks [220]
3 years ago
7

Choose the value of x that makes the open sentence true 40-x^2 < 2x+15.

Mathematics
2 answers:
S_A_V [24]3 years ago
6 0

I believe the answer is B, but I'm not 100% sure. :)


Anastasy [175]3 years ago
4 0

the answer is 5.



                                                hope it helps

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Day care centers expose children to a wider variety of germs than the children would be exposed to if they stayed at home more o
Ostrovityanka [42]

Answer:

a) The study is an observational study

b) The proportion of children with significant social activity in children with acute lymphoblastic leukemia is approximately 0.802

The proportion of children with significant social activity in children without acute lymphoblastic leukemia is approximately 0.8565

c) The odds ratio is approximately 0.6780

d) The 95% CI is approximately 0.523 < OR < 0.833

e) i) Yes

ii) Children with more social activity have a higher occurrence of acute lymphoblastic leukemia

Step-by-step explanation:

a) An experimental study is a study in which the researcher adds inputs to the study and then monitors the outcomes

An observational study is one in which the researcher observes risk factors and does not intervene in the process

Therefore, the study is an observational study

b) The proportion of children with significant social activity in children with acute lymphoblastic leukemia is \hat p_1 = 1020/1272 = 85/106 = 0.8\overline {0188679245283} ≈ 0.802

The proportion of children with significant social activity in children without acute lymphoblastic leukemia is \hat p_2 = 5343/6238 ≈ 0.8565

c) We have the following two way table;

\begin{array}{ccc}Lymphoblastic \ Leukemia &With \ Social \ Activity & Without \ Social \ Activity\\With&1020 \ (a)&252 \ (b)\\Without&5343 \ (c)&895 \ (d) \end{array}

The \ odds \ ratio = \dfrac{1,020 \times 895}{5,343 \times 252} \approx 0.6780

The odds ratio ≈ 0.6780

d) The 95% confidence interval for the odds ratio is given as follows;

95 \% \ CI = OR \ \pm \ 1.96 \times \sqrt{\dfrac{1}{a} +\dfrac{1}{b}+\dfrac{1}{c}+\dfrac{1}{d}}

Where;

a = 1020, b = 252, c = 5343, d = 895

Therefore;

95 \% \ CI \approx  0.6780 \ \pm \ 1.96 \times \sqrt{\dfrac{1}{1,020} +\dfrac{1}{252}+\dfrac{1}{5,343}+\dfrac{1}{895}} \approx 0.678 \pm0.155

The 95% CI ≈ 0.523 < OR < 0.833

e) i) Given that the observed Odds Ratio is within the Confidence Interval, therefore, there is an indication that the amount of social activity is associated with acute lymphoblastic leukemia

ii) Based on the proportion of the study findings, children with more social activity have a higher occurrence of acute lymphoblastic leukemia

6 0
2 years ago
The slope of a hill next to a highway decreases 2 vertical feet for every 3 horizontal feet away from the highway.
Novay_Z [31]

Slope is the change in Y ( vertical) over the change in X( horizontal).

The slope would be -2 /3

You would multiply the horizontal distance by the slope:

-2/3 x 12 = -8

The answer would be D. v(h)=-2/3h, and the vertical distance is -8 feet.

8 0
2 years ago
Show that x+y:x-y=3:2
ycow [4]

We have,

x+y:x-y=3:2

To prove that, x+ y : x - y = 3:2.

x+y=3  

And,

x+y = 2      

Adding (1) and (2), we get

x+y+x-y=3+2

⇒2x=5

⇒ x =

Put x =  in (1), we get

+y=3

⇒ y=3-=

x+y:x-y=

=3:2

So, x+y:x-y=3:2.

8 0
2 years ago
The local high school is hosting an ice cream social for new students. They record the ice cream choices of the students through
UkoKoshka [18]
3/7 is the correct answer

7 0
3 years ago
Read 2 more answers
Help asap pls! thanks :)
eduard

The correct answer would be A -2b ^^

HTH ^^

Brainliest would be great is possible! ^^

3 0
3 years ago
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