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Maurinko [17]
4 years ago
13

PLEASE HELP WILL GIVE 10 POINTS!!!!

Physics
2 answers:
Musya8 [376]4 years ago
6 0

Answer: Option (C) is the correct answer.

Explanation:

A quantitative data is defined as the data which can only be described in numbers or figures.  

For example, density of lead is 11.34 g/cm^{3}.

This is a quantitative data as density is represented in figures.

On the other hand, a data which describes the nature of a substance and that can only be described in words as there will be no figures or numerical data then it is known as a qualitative data.

For example, lead is solid at room temperature.

Thus, we can conclude that solid at room temperature is the property which Alisha placed in the wrong column.

agasfer [191]4 years ago
4 0
C because that isn't measurable that is can't be quantified
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A same-size iron ball and wooden ball are dropped simultaneously from a tower and reach the ground at the same time. The iron ba
Papessa [141]

Answer:

momentum of iron ball is greater than wooden ball

Explanation:

when metal ball (iron ball) and wooden drop are drop from same elevation and reaching the ground after same time. at this position the iron ball has greater momentum than wooden ball

we know that momentum is defined as

P=Mv

and we know also that mass of iron ball is greater than mass of wooden ball and they reached on ground at same time  and same distance it mean also velocity will be same for both ball. therefore from above relation we have

Miron*V > Mwood*V i.e.

momentum of iron ball is greater than wooden ball

5 0
4 years ago
Three children are struggling and pulling on a single toy. Two of the children, Abe and Barry, are EACH (individually) pulling w
3241004551 [841]

Solution :

c). $\vec{F}_A = $ force applied by Abe

   $\vec{F}_B = $ force applied by Barry

   $\vec{F}_E = $ force applied by Eric

   $\vec{F}_R = $ Resultant force

$\vec{F}_A $  in the vector form can be written as :

         $\vec{F}_A = 0 \hat{i} + 60 \hat{j}$

$\vec{F}_B $  in the vector form can be written as :

         $\vec{F}_B = 60 \hat{i} + 0 \hat{j}$

The resultant,

$\vec{F}_R= \vec{F}_A+\vec{F}_B $

     $=(0 \hat i + 60 \hat j)+(60 \hat i + 0\hat j)$

    $=60 \hat i + 60 \hat j$

$|\vec{F}_R| = \sqrt{60^2+60^2}$

        = 84.853 N

d). As the three forces are in equilibrium, therefore,

$|\vec F_E| = |\vec F_R|$

$|\vec F_E| =84.853 \ N$

e). The direction of the force exerted by Eric is exactly opposite to the direction of the resultant force.

The direction of the resultant force is :

$\theta = \tan ^{-1}\left(\frac{F_y}{F_x}\right)$

   $ = \tan ^{-1}\left(\frac{60}{60}\right)$

  = 45°  north east

The direction of the force E is  45° west or  45° south west.

   

8 0
3 years ago
PLEASE HELP WITH THIS QUESTION WILL GIVE BRAINLIST TO BEST ANSWER
lys-0071 [83]
The net force is 12 N to the left.
4 0
3 years ago
Read 2 more answers
What part of an electric circuit are the wires that carry the electric current
bezimeni [28]

Answer:

okay so, An electric circuit is a closed loop through which current can  actually flow. All electric circuits must have a voltage source, for example a battery, and a conductor, which is usually  a wire.

how does it flow or how does .current flow in a circuit ? When a wire is connected to battery terminals which is electrons, electrons flow from negative to positive. Electrons have a negative charge in case you didnt know. they are repelled from the negative and attracted to the positive.

if this helped please mark this as brainliest!!! :)

8 0
4 years ago
Car A starts out traveling at 35.0 km/h and accelerates at 25.0 km/h2 for 15.0 min. Car B starts out traveling at 45.0 km/h and
lawyer [7]

1 kilometre=1000 metre

      1 hour = 3600 second

       1\ km/hr=\frac{1000}{3600} m/s

       1\ km/hr=\frac{5}{18} m/s

The initial velocity of car A is 35.0 km/hr i.e

                                         35.0\ km/hr=35*\frac{5}{18} m/s

                                                                   = 9.72 m/s

The initial velocity of car B is 45 km/hr =12.5 m/s

The initial velocity of car C is 32 km/hr = 8.89 m/s

The initial velocity of car D is 110 km/hr=30.56 m/s

The acceleration of car A is given as  25\ km/hr^2

                                            =\ 25*\frac{1000}{3600*3600} m/s^2

                                            =0.00192901234 m/s^2

The time taken by car A = 15 min.

From equation of kinematics we know that-

                                 v= u+at      [Here v is the final velocity and a is the acceleration and t is the time]

Final velocity of A,  v = 9.72 m/s +[0.00192901234×15×60]m/s

                                   =11.456111106 m/s

The acceleration of B is given as    15\ km/hr^2

                                    =0.00115740740740 m/s^2

The time taken by car B =20 min

The final velocity of B is -

                             v= u+at

                               = u-at    [Here a is negative due to deceleration]

                               =12.5 m/s +[0.0011574074074×20×60]

                               =13.8888888.....

                               =13.9

The acceleration of C is given as    40\ km/hr^2          

                                                            =\ 0.003086419753 m/s^2

The time taken by car C =30 min

The final velocity of C is-

                                v = u+at

                                   =8.89 m/s+[0.003086419753×30×60] m/s

                                   =14.4455555555..m/s

                                   =14.45 m/s

The car C is decelerating.The deceleration is given as-  60\ km/hr^2

                                                                      =0.0046296296296m/s^2

The time taken by car D= 45 min.

The final velocity of the car D is-

                     v =u+at

                        =30.56 -[0.00462962962962×45×60]m/s

                        =18.06 m/s

Hence from above we see that the magnitude of final velocity car C and B is close to 15 m/s. The car C is very close as compared to car B.

                 


3 0
3 years ago
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