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Vladimir [108]
3 years ago
15

A group of hikers hear an echo 3.3 s after they shout. The temperature is 20◦C.

Physics
1 answer:
romanna [79]3 years ago
4 0

Answer:

560 m

Explanation:

The speed of sound in air is approximately:

v ≈ v₀ + 0.6T

where v₀ is the speed of sound at 0°C (273 K) in m/s, and T is the temperature in Celsius.

The speed of sound at 20°C at that altitude is:

v ≈ 327 + 0.6(20)

v ≈ 339 m/s

The sound travels from the hikers to the mountain and back again, so it travels twice the distance.

339 m/s = 2d / 3.3 s

2d = 1118.7 m

d = 559.35 m

Rounding, the mountain is approximately 560 m away.

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No

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What is the answer for this question please?​
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In a lab environment, you are investigating the impulse of a force exerted on a brick when the brick's speed is reduced from 2.5
BabaBlast [244]

Answer:

The impulse is the same in both situations.

Explanation:

As we know that impulse is defined as change in momentum

so it is given as

\Delta P = m(v_f - v_i)

also we know that

\Delta P = F\Delta t

so we will have

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8 0
4 years ago
An electric potential at x = 0 cm is 300 V, -100 V at x = 5 cm, and varies linearly with x. If a positive charge is released fro
lions [1.4K]

Answer:

Moves to the right

Explanation:

Given:

- Right side @ x = 5 cm is at - 100 V

- Left side @ x = 0 cm is at 300 V

- Charge is placed @ x = 2.5 cm

Find:

- The direction of motion of + charge when released from its position.

Solution:

- We know that Electric field is always perpendicular to equi-potential lines. Hence it points out from the left side towards the right hand side. So the Electric field at the point of charge @ x = 2.5 cm, is directed towards the right that would also be the direction of motion of the positive charge.

5 0
3 years ago
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A hockey stick stores 4.2 J of potential energy when it is bent 3.1 cm. Treating the hockey stick as a spring, what is its sprin
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Answer:

Spring constant, k = 8740.89 N/m

Explanation:

Given the following data;

Potential energy = 4.2 J

Extension, e = 3.1 cm to meters = 3.1/100 = 0.031 m

To find the spring constant;

Mathematically, the potential energy stored in a spring is given by the formula;

P.E = \frac {1}{2}Kx^{2}

Where;

P.E is potential energy.

K is the spring constant.

x is the extension of the spring.

Substituting into the equation, we have;

4.2 = \frac {1}{2}*k*0.031^{2}

Cross-multiplying, we have;

8.4 = k*0.000961

k = \frac {8.4}{0.000961}

Spring constant, k = 8740.89 N/m

3 0
3 years ago
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