All categories

3 years ago

3x squared -2x -5 = 0

Mathematics

1 answer:

Firlakuza [10]3 years ago

7 0

X is -1 and 5/3........

You might be interested in

Need help understanding what to do

Juliette [100K]

I believe you are expected to simplify. To do this all you do is group like terms (x, x², x³ etc.) and then simplify the coefficients.

13. 10z + 7z - 19z² - 5z² - 17z

first you can rearrange and group like terms (remember the bring the sign in front of each term with it). I would do it like this:
-19z² - 5z² +10z + 7z - 17z

Now simplify the coefficients:

-24z² + 0z

you can omit the 0z and your simplified answer is

-24z²

Main thing to remember here is that z and z² cannot be simplified together, nor can any variable that has an exponent because the exponent makes them differ.

6 0

3 years ago

What is the 185th digit of the following pattern 12345678910111213141516

Sphinxa [80]

Answer:

185

Step-by-step explanation:

1,2,3,4,5,6,7,8,9,10,11,12,13,14,15,16,17,18,19,2021.22,23,24,25,26,27,28,29,30,31,32,33,34,35,36,37,38,39,40

I give up

7 0

3 years ago

G(x)=-3x-8<br>g( )=10<br>what does x equal?

Nikolay [14]

Answer: X = 24/G

G = 24/x

Step-by-step explanation:

6 0

3 years ago

Wht does ^ this mean?

Ainat [17]

Answer:

Concept: Analysis

The carrot means an exponent.
${x}^{2}$
It means something like x^2

8 0

3 years ago

Evaluate S5 for 300 + 150 + 75 + … and select the correct answer below. 18.75 93.75 581.25 145.3125

Savatey [412]

we have that

$300 + 150 + 75 +...$

Let

$a1=300\\ a2=150\\ a3=75$

we know that

$\frac{a2}{a1} =\frac{150}{300} \\\\ \frac{a2}{a1}=0.5 \\ \\ a2=a1*0.50$

$\frac{a3}{a2} =\frac{75}{150} \\\\ \frac{a3}{a2}=0.5 \\ \\ a3=a2*0.50$

$a(n+1)=an*0.50$

Is a geometric sequence

Find the value of $a4$

$a(4)=a3*0.50$

$a(4)=75*0.50$

$a(4)=37.5$

Find the value of $a5$

$a(5)=a4*0.50$

$a(5)=37.5*0.50$

$a(5)=18.75$

Find $S5$

$S5=a1+a2+a3+a4+a5\\ S5=300+150+75+37.5+18.75\\ S5=581.25$

therefore

the answer is

$581.25$

Alternative Method

Applying the formula

$S_n=\frac{a_1 (1-r^n)}{1-r} \\\\a_1=300 \\ r=\frac{1}{2}\\\\ S_5=\frac{300(1-(\frac{1}{2})^5)}{1-\frac{1}{2}}\\\\=\frac{300(1-\frac{1}{32})}{\frac{1}{2}}\\\\=\frac{300 \times \frac{31}{32}}{\frac{1}{2}}\\\\=\frac{75 \times \frac{31}{8}}{\frac{1}{2}}\\\\=\frac{\frac{2325}{8}}{\frac{1}{2}}\\\\=\frac{2325}{8} \times 2\\\\=\frac{2325}{4}\\\\=581 \frac{1}{4}\\\\=581.25$

therefore

the answer is

$581.25$

6 0

3 years ago

Read 2 more answers