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Basile [38]
3 years ago
15

Which of the following are valid names for the given triangle? check all that apply

Mathematics
2 answers:
Sliva [168]3 years ago
6 0
B, C, and D. you name a triangle with the corners, not the sides.
sweet-ann [11.9K]3 years ago
3 0

Answer:

B) XMA; C) MAX; and D) AXM

Step-by-step explanation:

A triangle is named based on its vertices.  The vertices of this angle are A, M and X; this means any combination of these three letters can be used to name the triangle.

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Please ANSWER THE ANSWER HAS TO BE A INTEGER OR A DECIMAL.
Natali [406]

Answer: 4.3

Step-by-step explanation: To find the range you have to subtract the highest number by the lowest number. So you'd subtract 2.6 by -1.7. And since -1.7 is already a negative number, it would get turned into a positive.

5 0
3 years ago
Read 2 more answers
5.)which of the following is the best example of pair of lines that are parallel?
sergij07 [2.7K]

Answer:

D

Step-by-step explanation:

D because it is the only choice that obtains things that do not intersect or cross each other at some point. The doors would never cross, unlike the windows or roadways or railways.

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4 0
3 years ago
Find the nth taylor polynomial for the function, centered at c. f(x) = ln(x), n = 4, c = 5
masha68 [24]

The nth taylor polynomial for the given function is

P₄(x) = ln5 + 1/5 (x-5) - 1/25*2! (x-5)² + 2/125*3! (x-5)³ - 6/625*4! (x - 5)⁴

Given:

f(x) = ln(x)

n = 4

c = 3

nth Taylor polynomial for the function, centered at c

The Taylor series for f(x) = ln x centered at 5 is:

P_{n}(x)=f(c)+\frac{f^{'} (c)}{1!}(x-c)+  \frac{f^{''} (c)}{2!}(x-c)^{2} +\frac{f^{'''} (c)}{3!}(x-c)^{3}+.....+\frac{f^{n} (c)}{n!}(x-c)^{n}

Since, c = 5 so,

P_{4}(x)=f(5)+\frac{f^{'} (5)}{1!}(x-5)+  \frac{f^{''} (5)}{2!}(x-5)^{2} +\frac{f^{'''} (5)}{3!}(x-5)^{3}+.....+\frac{f^{n} (5)}{n!}(x-5)^{n}

Now

f(5) = ln 5

f'(x) = 1/x ⇒ f'(5) = 1/5

f''(x) = -1/x² ⇒ f''(5) = -1/5² = -1/25

f'''(x) = 2/x³  ⇒ f'''(5) = 2/5³ = 2/125

f''''(x) = -6/x⁴ ⇒ f (5) = -6/5⁴ = -6/625

So Taylor polynomial for n = 4 is:

P₄(x) = ln5 + 1/5 (x-5) - 1/25*2! (x-5)² + 2/125*3! (x-5)³ - 6/625*4! (x - 5)⁴

Hence,

The nth taylor polynomial for the given function is

P₄(x) = ln5 + 1/5 (x-5) - 1/25*2! (x-5)² + 2/125*3! (x-5)³ - 6/625*4! (x - 5)⁴

Find out more information about nth taylor polynomial here

brainly.com/question/28196765

#SPJ4

3 0
2 years ago
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