Answer:
20/3 ounces of water is added.
Step-by-step explanation:
how many ounces of pure water should be added to 20 ounces of 40% solution of muriatic acid to obtain a 30% solution of muriatic acid?
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The acid is 40% of 20 ounces = 8 ounces.
0.4*20 = 8
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That same 8 ounces is to be 30%. The water will be the other 70%.
8/30 = x/100
30x = 800
x = 80/3, the total amount of the solution.
We started with 20, so 80/3 - 20 = 20/3
0.0378
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y = 3x + 15
1. Find the reciprocal of the slope and change signs: -3
2. y = 3x + b
3. Plug in x and y --> b = 15
4. Make your equation using y = mx + b: y = 3x + 15
