Question

In the accompanying diagram of right triangle ABC, the hypotenuse if AB, AC = 3, BC = 4, and AB = 5. Sin B is equal to

Answer 1

Answer:$sin(B)=\frac{3}{5}$

Step-by-step explanation:

We are given that a triangle ABC is a Right Angled Triangle. The side AB is hypotenuse, so the angle opposite to side AB which will be angle C is a Right Angle (measures 90 degrees)

We have the side length of all 3 sides. Based on this information, we can construct a triangle with given measures. The triangle is shown in the attached image.

We have to find the value of Sin(B). Sin of an angle is defined as:

$sin(\theta)=\frac{\text{Opposite Side}}{\text{Hypotenuse}}$

The side opposite to angle B is AC with a length of 3 and hypotenuse is side AB with length 5. So Sin of angle B would be:

$sin(B)=\frac{3}{5}$