Calculate the probability that both bids are successful
Answer:
The probability that both contracs are successful is 0.21
Step-by-step explanation:
Given
E1 = the event that the bid on the first contract is successful
E2 = the event that the bid on the second contract is successful
P(E1) = 0.3
P(E2) = 0.7
Let P(A) represent the event that both contracts are successful
P(A) = P(E1 and E2)
Since both events are independent. P(A) becomes
P(A) = = P(E1 * P(E2)
By substituton
P(A) = 0.3 * 0.7
P(A) = 0.21
Hence the probability that both contracs are successful is 0.21
Answer:
x=3
Step-by-step explanation:
When you substitute x = 3 to both equations, you get y = -4 for both so that is a solution
1) his time would have to be less than 11.54
2)each member would have to run a time of about 11.91
3) Assuming that Dwane ran a time of 11.53 the average amount of time it took each member to run the 100 meters will be about 12.2 seconds per 100 meters
<span>
3√(32x^8y^10)
= </span><span>3√(16*2 x^8y^10)
= 12x^4y^5 </span>√2
Hope it helps
