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gregori [183]
2 years ago
10

Germanium is a group 4A semiconductor. The addition of a dopant atom (group 3A element) that has fewer valence electrons than th

e host atom results in a p-type semiconductor. The addition of a dopant atom (group 5A elements) that has more valence electrons than the host atom results in an n-type semiconductor. Which of the following elements when used for doping germanium will yield p-type semiconductors, and which elements when used for doping germanium will yield n-type semiconductors?
Chemistry
1 answer:
klasskru [66]2 years ago
7 0

Answer:

Doping with galium or indium will yield a p-type semiconductor while doping with arsenic, antimony or phosphorus will yield an n-type semiconductor.

Explanation:

Doping refers to improving the conductivity of a semiconductor by addition of impurities. A trivalent impurity leads to p-type semiconductor while a pentavalent impurity leads to an n-type semiconductor.

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What role do guanacos play in the Andes Mountains ecosystem?.
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Grasses and plants are producers, guanacos are herbivores and are primary consumers and pumas are predators and secondary consumers

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2 years ago
Calculate the molar mass of NH4NO3. Molar mass of NH4NO3 = g/mol.
bija089 [108]

The molar mass of NH4NO3 in g/mol is 80g/mol.

HOW TO CALCULATE MOLAR MASS:

The molar mass of a compound can be calculated by summing the atomic masses of its constituent elements.

In ammonium nitrate (NH4NO3), there are nitrogen, hydrogen, and oxygen elements.

  • Atomic mass of nitrogen = 14
  • Atomic mass of oxygen = 16
  • Atomic mass of hydrogen = 1

Molar mass of NH4NO3 = 14 + 1(4) + 14 + 16(3)

Molar mass of NH4NO3 = 80g/mol

  • Therefore, the molar mass of NH4NO3 in g/mol is 80g/mol.

Learn more about molar mass at: brainly.com/question/8101390?referrer=searchResults

4 0
2 years ago
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The illustration depicts the formation of an ionic chemical bond between lithium and fluorine atoms. Why is the resulting compou
nirvana33 [79]
<span>The transferred electron from lithium to fluorine provides each atom with a full outer energy level.</span>
7 0
2 years ago
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A student carefully placed 15.6 g of sodium in a reactor supplied with chlorine gas. When the reaction was complete, the student
BabaBlast [244]

Answer:

24.09 grams of chlorine gas reacted.

Explanation:

2Na(s)+Cl_2(g)\rightarrow 2NaCl(s)

Moles of sodium chloride = \frac{39.7 g}{58.5 g/mol}=0.6786 mol

According to reaction, 2 moles of  NaCl are formed from 1 mole chlorine gas.

Then 0.6786 moles of NaCl will be formed from;

\frac{1}{2}\times 0.6786 mole=0.3393 mol

Mass of 0.3393 moles of chlorine  gas:

0.3393 mol × 71 g/mol = 24.09 g

24.09 grams of chlorine gas reacted.

5 0
3 years ago
How many grams are in 44.8 liters of nitrogen gas, n2?<br> a) 56g<br> b) 27g<br> c) 36g<br> d) 112g
kkurt [141]

a) 56g

<h3>Calculation:</h3>

At STP,

22.4 L of N₂ = 1 mol

We have given 44.8 L of N₂, therefore,

44.8 L of N₂ = \frac{44.8}{22.4}

                    = 2 mol

We know that,

1 mol of N₂ = 28 g

Hence,

2 mol of N₂ = 28 × 2

                   = 56g

Hence, there are 56 g of N₂ in 44.8 L of nitrogen gas.

Learn more about calculation at STP here:

brainly.com/question/9509278

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2 years ago
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