1answer.
Ask question
Login Signup
Ask question
All categories
  • English
  • Mathematics
  • Social Studies
  • Business
  • History
  • Health
  • Geography
  • Biology
  • Physics
  • Chemistry
  • Computers and Technology
  • Arts
  • World Languages
  • Spanish
  • French
  • German
  • Advanced Placement (AP)
  • SAT
  • Medicine
  • Law
  • Engineering
frosja888 [35]
3 years ago
13

Finish the lyrics.

Chemistry
1 answer:
pav-90 [236]3 years ago
8 0
Kg it it ig itchy it ig ig igxgixigxigc
You might be interested in
What is the effect on this???
Setler79 [48]
It being transmitted
7 0
3 years ago
what criteria are likely to dictate certain pairs of elements to undergo ionic bonding and others covalent bonding?
Paha777 [63]

Answer:

If one element is a metal and the other element is a non metal

Explanation:

Ionic bonds are formed between metals and non metals. The nonmetal atom receives electron(s) from a metal atom to form an ionic substance. This means that ionic substances are basically an ion pair.

Covalent bonds are mostly formed between two nonmetals. These elements share electrons with each other in order to form the compound.

7 0
2 years ago
Alkynes have what in<br> common with alkenes ?
jonny [76]

Answer:

Alkanes, alkenes and alkynes are simple hydrocarbon chains with no functional groups. Alkanes are identified because the carbon chain has only single bonds. Alkenes have at least one double bond and alkynes have at least one triple bond. The most common alkyne is ethyne, better known as acetylene.

8 0
2 years ago
Consider the reaction. mc014-1.jpg How many grams of methane should be burned in an excess of oxygen at STP to obtain 5.6 L of c
garri49 [273]
The reaction for the combustion of methane can be expressed as follows.
                           CH4 + 2O2 --> CO2 + 2H2O
We solve first for the amount of carbon dioxide in moles by dividing the given volume by 22.4L which is the volume of 1 mole of gas at STP.
                            moles of CO2 = (5.6 L) / (22.4 L/1 mole)
                             moles of CO2 = 0.25 moles
Then, we can see that every mole of carbon dioxide will need 1 mole of methane
                              moles methane = (0.25 moles CO2) x (1 moles O2/1 mole CO2)
                                                    = 0.25 moles CH4
Then, multiply this by the molar mass of methane which is 16 g/mole. Thus, the answer is 4 grams methane. 
5 0
3 years ago
Read 2 more answers
If the weight of displaced liquid and the weight of an object are the same, the object will:
s344n2d4d5 [400]

Answer:

Float

Explanation:

If the weight of liquid displaced and the weight of an object are the same, the object will float in the liquid.

From Archimedes principle, when an object is immersed in fluid, a force called upthrust supports it and it equal to the weight of the liquid displaced.

When in a liquid, the weight of the liquid displaced is the same as that of the of the object, it will float and not sink.

7 0
3 years ago
Other questions:
  • What is the one way the otter is adapted to living in the moving water of a river
    15·1 answer
  • What is the rise and fall of ocean water are called
    10·2 answers
  • A 1.00-degree increase on the Celsius scale is equivalent to a 1.80-degree increase on the Fahrenheit scale. The temperature of
    12·2 answers
  • What is the theoretical yield of hydrogen gas if 5.00 mol of zinc are added to an excess of hydrochloric acid?
    13·2 answers
  • 3.
    9·1 answer
  • At 400 k, the equilibrium constant for the reaction is kc = 7.0. br2 (g) + cl2 (g) 2brcl (g) a closed vessel at 400 k is charged
    5·1 answer
  • Which formula should be used to calculate pressure and temperature changes if the volume remains constant
    15·1 answer
  • A sample of ethanol has a mass of 36.7 g.
    13·2 answers
  • The percentage by mass of Br in the compound
    5·2 answers
  • C. By examining the physical and chemical properties of evidence at a crime scene, investigators can
    14·1 answer
Add answer
Login
Not registered? Fast signup
Signup
Login Signup
Ask question!