Answer:
Explanation:
<u>Given Data:</u>
Initial Volume = 
= 7.0 L
Initial Temperature = 
= 300 °C + 273 = 573 K
Final Temperature = = 25.0 °C + 273 = 298 K
<u>Required:</u>
Final Volume = 
= ?
<u>Formula:</u>
<u>[Charles Law] </u>
<u>Solution:</u>
Put the givens
![\displaystyle \frac{7}{573 } =\frac{V_2}{298} \\\\0.01 = \frac{V_2}{298} \\\\\times 298 \ to \ both \ sides\\\\0.01 \times 298 = V_2\\\\3.64 \ L =V_2\\\\\boxed{V_2 =3.64 \ L}\\\\\rule[225]{225}{2}](https://tex.z-dn.net/?f=%5Cdisplaystyle%20%5Cfrac%7B7%7D%7B573%20%7D%20%3D%5Cfrac%7BV_2%7D%7B298%7D%20%5C%5C%5C%5C0.01%20%3D%20%5Cfrac%7BV_2%7D%7B298%7D%20%5C%5C%5C%5C%5Ctimes%20298%20%5C%20to%20%5C%20both%20%5C%20sides%5C%5C%5C%5C0.01%20%5Ctimes%20298%20%3D%20V_2%5C%5C%5C%5C3.64%20%5C%20L%20%3DV_2%5C%5C%5C%5C%5Cboxed%7BV_2%20%3D3.64%20%5C%20L%7D%5C%5C%5C%5C%5Crule%5B225%5D%7B225%7D%7B2%7D)
You mix 35mL of 0.54M NaI with 14mL of 0.84M Pb(NO3)2.
Equation: 2H₂ + O₂ → 2H₂O
Now, Given mass of Oxygen = 192 g
Molar mass of Oxygen = 16 g/mol
No. of moles in Oxygen = 16/192 = 0.0833
Now, for every mole of Oxygen, 2 mole of Hydrogen will form,
so, Number of moles of Hydrogen = 0.0833 * 2 = 0.167
Given mass = Number of Moles * Molar mass
Given mass = 0.167 * 2
m = 0.33 g
In short, Your Answer would be: 0.33 g
Hope this helps!
Answer:
One possible answer could be lemon juice
Explanation:
We had to do a water test, and I was looking up what pH levels were. Then I learned about it in school, so I know a thing or two about it :)
Possible other answers include stomach acid and cola.
Hope this helps!!
