Answer:
1) 4
2) 1.5
3) 8
4) 1
5) 5
6) 9
Step-by-step explanation:
<h3>
1)</h3><h3>
√16</h3>
= √(4x4)
= √(4)²
<h3>= 4</h3>
<h3>
2)</h3><h3>
√2.25</h3>
= √(9/4)
= √(3x3)/(2x2)
= √(3)²/(2)²
= 3/2
<h3>= 1.5</h3>
<h3>3)</h3><h3>6² ÷ 9 x 2 </h3>
= 36 ÷ 9 x 2
= 36 x 1/9 x 2
= 36/9 x 2
= 12/3 x 2
= 4 x 2
<h3>= 8</h3>
<h3>4)</h3><h3>12-2 / 6+4</h3>
= 10/10
<h3>= 1</h3><h3 /><h3>5)</h3><h3>√(16+9)</h3>
= √(25)
= √(5x5)
= √(5)²
<h3>= 5</h3><h3 /><h3>6)</h3><h3>63 ÷ 3² + |2|</h3>
= 63 ÷ 9 + |2|
= 63/9 + |2|
= 21/3 + |2|
= 7 + |2|
<h3>= 9</h3>
Answer:
2 : 5, or 2/5
Step-by-step explanation:
4 : (3 + 3 + 4) =4 : 10 = 2 : 5
Answer:
Step-by-step explanation:
1. 2x - 28
2. 6x3 - 4x2 + 2x
3. x2 + 7x + 12
4. m2 - 4mn + 21n2
5. x2 - 9x + 18
Answer:
b
Step-by-step explanation:
CR and DS are perpendiculars dropped from AB to PQ , and AB is perpendicular to CR and DS
Answer:
When a moving car applies brake or stop . In this situation result in a final value is zero .
Hope this will be helpful to you..
