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BaLLatris [955]
3 years ago
14

Find the product: 5(−3)(−2)

Mathematics
2 answers:
stellarik [79]3 years ago
7 0
Product means to multiply.

Multiply the first 2 numbers , then multiply the answer of that to the 3rd number:

5 * -3 = -15

-15 * -2 = 30

The answer is 30
Nitella [24]3 years ago
6 0
Hey Friend!!!
Answer-30
You might be interested in
Someone please help me !
Leni [432]

Answer:

Can't tell if it went through...

1. Shop A = 2x

2. Shop B = 2x - 580

3. Total = Shop A + Shop B

1949 = 2x + 2x - 580

4. Combine like terms

2x + 2x = 4x

1949 = 4x - 580

5. Add 580 to both sides (to remove -580 from right side)

1949 + 580 = 4x - 580 + 580

2529 = 4x

6. Divide both sides by 4 (to get x)

2529 / 4 = 4x / 4

632.25 = x

7. Shop A = 2x

2 * 632.25 = 1264.50

Shop A = 1264.50

8. Shop B = 2x - 580

2 * 632.25 - 580 = 684.50

Shop B = 684.50

Check: Shop A + Shop B = 1949

1264.50 + 684.50 = 1949

Shop A = 1264.50

Shop B = 684.50

Step-by-step explanation:

8 0
3 years ago
Complete the following table for residuals for the linear function f(x) = 138.9x − 218.76. (Round to the hundredths place)
OLEGan [10]

<em>Answer:</em>

<h3><em>i believe it is 65 if it isnt then idk</em></h3>

<em>Step-by-step explanation:</em>

6 0
3 years ago
What is 125 divided by 5? How do we do it in friendly parts
Bess [88]
125 divided by 5 is 25. hope this helped but im not to sure what friendly parts are sorry
7 0
3 years ago
At a competition with 6 runners, 2 medals are awarded for first and second
insens350 [35]

Answer:

30 ways

Step-by-step explanation:

The first medal can be awarded in 6 different ways since any of the runners could have it. Once the first medal is awarded, the second medal can only be given to any of the 5 runners available.

So there are 6x5=30 different ways to award the medals

3 0
3 years ago
The table below represents the function f
alukav5142 [94]

Answer:

1

Step-by-step explanation:

I belive its one because 3^2  is 9 and 9+1 = 10

to make sure  it not just once 3^3 is 27 and 27+1=28

3 0
3 years ago
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