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3 years ago

Find the slope of the line that contains the points named.

Mathematics

2 answers:

MariettaO [177]3 years ago

6 0

Answer:

A -1.

Step-by-step explanation:

Using the slope formula for 2 points:

The slope = ((c + d) - (c - d) / (c - d) - (c + d))

= 2d / -2d

= -1.

Alina [70]3 years ago

5 0

Answer:

Answer A

Step-by-step explanation:

slope= (c+d-(c-d))/(c-d-(c+d))=2d/(-2d)=-1

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Solve for x using the Quadratic Formula: x2 + 4x + 4 = 0<br> -b + Vb2 - 4ac<br> x=<br> 2a

Irina18 [472]

Answer:

x = -2.

Step-by-step explanation:

In this case, a is 1, b is 4 and c is 4.

-4 plus or minus the square root of 4^2 - 4 * 1 * 4 divided by 2 * 1 = -4 plus or minus the square root of 16 - 16 / 2 = -4 plus or minus the square root of 0 / 2 = -4 / 2 = -2.

x = -2.

Hope this helps!

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3 years ago

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Answer:

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Step-by-step explanation:

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3 years ago

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Amiraneli [1.4K]

Answer:

145.9

Step-by-step explanation:

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3 years ago

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Eva8 [605]

Answer:

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Step-by-step explanation:

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3 years ago

At what angle does a diffraction grating produce a second-order maximum for light having a first-order maximum at 20.0 degrees?

hichkok12 [17]

Answer:

At 43.2°.

Step-by-step explanation:

To find the angle we need to use the following equation:

$d*sin(\theta) = m\lambda$

Where:

d: is the separation of the grating

m: is the order of the maximum

λ: is the wavelength

θ: is the angle

At the first-order maximum (m=1) at 20.0 degrees we have:

$\frac{\lambda}{d} = \frac{sin(\theta)}{m} = \frac{sin(20.0)}{1} = 0.342$

Now, to produce a second-order maximum (m=2) the angle must be:

$sin(\theta) = \frac{\lambda}{d}*m$

$\theta = arcsin(\frac{\lambda}{d}*m) = arcsin(0.342*2) = 43.2 ^{\circ}$

Therefore, the diffraction grating will produce a second-order maximum for the light at 43.2°.

I hope it helps you!

6 0

3 years ago