Step-by-step explanation:
The solution to this problem is very much similar to your previous ones, already answered by Sqdancefan.
Given:
mean, mu = 3550 lbs (hope I read the first five correctly, and it's not a six)
standard deviation, sigma = 870 lbs
weights are normally distributed, and assume large samples.
Probability to be estimated between W1=2800 and W2=4500 lbs.
Solution:
We calculate Z-scores for each of the limits in order to estimate probabilities from tables.
For W1 (lower limit),
Z1=(W1-mu)/sigma = (2800 - 3550)/870 = -.862069
From tables, P(Z<Z1) = 0.194325
For W2 (upper limit):
Z2=(W2-mu)/sigma = (4500-3550)/879 = 1.091954
From tables, P(Z<Z2) = 0.862573
Therefore probability that weight is between W1 and W2 is
P( W1 < W < W2 )
= P(Z1 < Z < Z2)
= P(Z<Z2) - P(Z<Z1)
= 0.862573 - 0.194325
= 0.668248
= 0.67 (to the hundredth)
Answer:
Step-by-step explanation:
If we are given the quadratic model, we know that the height of anything on the ground is 0 meters, so that model becomes
I changed your x's to t's since t is for time.
Now we need to factor that quadratic and solve for time:
Since -2 definitely does not equal 0, then
Factor that and find t values of 4 and -2. Again, we know that time will never be negative, so
t = 4 seconds.
Answer:
slope= 10/9
y intercept= -11/9
Step-by-step explanation:
9y= 10x -11
y= 10/9x -11/9
slope= 10/9
y intercept= -11/9
Answer:
1/2
Step-by-step explanation:
Answer:
n = -7
Step-by-step explanation:
49 = -5n - 2n
combine like terms
-5 - 2 = -7
49 = -7n
divide both sides by -7
49/-7 = -7n/-7
49/-7 = n
49/-7 = -7
-7 = n
