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Alex777 [14]
3 years ago
11

In covalent bonding, nonmetal atoms _____ electrons that typically result in filled s and p orbitals. A) lose B) gain C) share D

) transfer
Chemistry
1 answer:
Mama L [17]3 years ago
3 0

Nonmetal atoms would share electrons in a covalent bonding.

Hope this helped! :D

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For the isopropyl alcohol solution, what types of intermolecular forces would be experienced by the FD and; C Red 40, Blue 1 and
IgorLugansk [536]

Answer:

Hi

Isopropyl alcohol is a colorless, flammable liquid with an intense smell and miscible with water. It is an isomer of 1-propanol. It is obtained by means of a hydration reaction with propylene. It is also produced by hydrogenation of acetone. There are two main ways for the process of hydrating propylene: indirect hydration by sulfuric acid and direct hydration. The type of bond that presents hydrogen bonds and dipole-dipole forces.

Explanation:

4 0
3 years ago
Convert 0.0598 to scientific notation​
ziro4ka [17]
The scientific notation is 5.98 * 10^-2
6 0
3 years ago
Read 2 more answers
The reaction 2CH4(g)⇌C2H2(g)+3H2(g) has an equilibrium constant of K = 0.154. If 6.30 mol of CH4, 4.20 mol of C2H2, and 11.15 mo
boyakko [2]

Answer:

C₂H₂ + 3H₂ ⟶ 2CH₄  

Explanation:

The initial concentrations are:

[CH₄] = 6.30 ÷ 6.00 =   1.05  mol·L⁻¹

[C₂H₂] = 4.20 ÷ 6.00 = 0.700 mol·L⁻¹

   [H₂] = 11.15 ÷  6.00 =  1.858 mol·L⁻¹

                2CH₄ ⇌ C₂H₂ + 3H₂

I/mol·L⁻¹:    1.05     0.700   1.858

Q = \dfrac{\text{[C$_{2}$H$_{2}$][H$_{2}$]}^{3}}{\text{[CH$_{4}$]}^{2}} = \dfrac{ 0.700\times 1.858^{3}}{1.05^{2}}= 4.07

Q > K

That means we have too many products.

The reaction will go to the left to get rid of the excess products.

C₂H₂ + 3H₂ ⟶ 2CH₄

8 0
4 years ago
The voltage for the following cell is +0.731 V. Find Kb for the organic base RNH2. Use EscE 0.241V.
tino4ka555 [31]

Complete Question

The complete question is shown on the first uploaded image  

Answer:

The  value is   K_b  =   1.89 *10^{-6}

Explanation:

From the question we are told that

   The  voltage of the cell is  V  =  0.731 \  V

Generally K_b is mathematically represented as  

           K_b  =  \frac{K_w }{ K_a }

Where  K_w  is the equilibrium constant for this auto-ionization of water with a value  K_w  =  1.0 *10^{-14}

Generally the E_{cell} is mathematically represented as

       E_{cell} =  V  -  E_{SCE}

=>     E_{cell} =  0.731 - 0.241

=>       E_{cell} =   0.49 V

This  E_{cell} is mathematically represented as

             E_{cell} =  \frac{0.0592}{n} *  log K_a

Where n is the number of moles which in this question is  n = 1

         So  

         0.490 =  \frac{0.0592}{1}  *  log K_a

=>      K_a  =  5.30*10^{-9}

So  

     K_b  =  \frac{ K_w}{ K_a}

=>   K_b  =  \frac{1.0 *10^{-14}}{ 5.30*10^{-9}}

=>    K_b  =   1.89 *10^{-6}

5 0
3 years ago
__________________ are high-speed bands of winds occurring at the top of the tropsophere.
chubhunter [2.5K]

Answer:

jet streams

Explanation:

THE JET STREAM Narrow bands of exceedingly high speed winds are known to exist in the higher levels of the atmosphere at altitudes ranging from 20,000 to 40,000 feet or more. They are known as jet streams.

7 0
3 years ago
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