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Alex777 [14]
3 years ago
11

In covalent bonding, nonmetal atoms _____ electrons that typically result in filled s and p orbitals. A) lose B) gain C) share D

) transfer
Chemistry
1 answer:
Mama L [17]3 years ago
3 0

Nonmetal atoms would share electrons in a covalent bonding.

Hope this helped! :D

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How much do 15.26 moles of silver weigh in grams? Enter a number.
galina1969 [7]
15.26 miles of silver is 0.1414689408 grams
7 0
3 years ago
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what electronic transition in a hydrogen atom starting from n=7 energy level will produce infrared radiation with energy of 55.1
Lostsunrise [7]

Answer:

(<em>n</em> = 7) ⟶ (<em>n</em> = 4)

Explanation:

1. Convert the energy to <em>joules per mole of electrons</em>.  

<em>E</em> = 55.1 × 1000 = 55 100 J/mol

2. Convert the energy to <em>joules per electron </em>

<em>E</em> = 55 100/(6.022 × 10²³)

<em>E</em> = 9.150 × 10⁻²⁰ J/electron

3. Use the Rydberg equation to <em>calculate the transition </em>

Rydberg's original formula was in terms of wavelengths, but we can rewrite it to have the units of energy. The formula then becomes  

\Delta E = R_{\text{H}} (\frac{ 1}{ n_{f}^{2}} - \frac{ 1}{ n_{i}^{2}})

where  

R_{\text{H}} = the Rydberg constant = 2.178 × 10⁻¹⁸ J

n_{i} and n_{f} are the initial and final energy levels.

9.150 \times 10^{-20} = 2.178 \times 10^{-18}(\frac{ 1}{ n_{f}^{2}} - \frac{ 1}{ 7^{2}})      

\frac{9.150 \times 10^{-20} }{2.178 \times 10^{-18}} = \frac{ 1}{ n_{f}^{2}} - \frac{ 1}{ 49}

\frac{ 1}{ n_{f}^{2}} = \text{0.042 01} + \frac{1 }{49 }

\frac{ 1}{ n_{f}^{2}} = \text{0.042 01 + 0.020 41}

\frac{ 1}{ n_{f}^{2}} = \text{0.042 01 + 0.020 41}

\frac{ 1}{ n_{f}^{2}} = \text{0.062 42}

n_{f}^{2} = \frac{1 }{ \text{0.062 42}}

n_{f}^{2} = 16.02

n_{f} = \sqrt{16.02}

n_{f} = 4.003 \approx 4

4 0
3 years ago
How much Cu-64 (half-life about 12 hours) would remain from a 2 mg sample after 12 hours?​
Bogdan [553]

Answer:

i beleive it is  A if not here a cookie online cookie also dont forget to wear your mask kiddos

Explanation:

7 0
3 years ago
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Potassium hydroxide, also known as lye, dissociates into metal and hydroxide ions in water.
lesya692 [45]

Answer:

strong acid and weak base

Explanation:

#carryonlearning

5 0
3 years ago
How much water, in grams, can be made from
Aleks [24]

Answer:

m_{H_2O}=73.0gH_2O

Explanation:

Hello there!

In this case, since the formation of water from hydrogen and oxygen is:

2H_2+O_2\rightarrow 2H_2O

Whereas we find a 2:2 mole ratio of hydrogen to water. In such a way, by using the Avogadro's number, the aforementioned mole ratio and the molar mass of water (18.02 g/mol), we obtain the following grams of water product:

m_{H_2O}=2.44x10^{24}molec*\frac{1molH_2}{6.022x10^{23}molec}*\frac{2molH_2O}{2molH_2}*\frac{18.02gH_2O}{1molH_2O}\\\\   m_{H_2O}=73.0gH_2O

Regards!

6 0
3 years ago
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