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Ugo [173]
3 years ago
14

What is the most complete answer below about the information, found about the element uranium in the periodic table

Chemistry
1 answer:
jonny [76]3 years ago
6 0

Answer:

92 is that atomic number and 238.03 is the atomic mass number

Explanation:

The structure of the atom is given as:

                    ⁹²₂₃₈.₀₃U

The number 92 is the atomic number of the atom.

  The atomic number is the number of protons within an atom. This number defines the nature and type of atom that we have.

238.03 is the atomic mass number;

  The is the number of protons and neutrons within an atom. It is typically the mass of nucleus.

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Which properties can be measured without changing the chemical composition of the matter? _______ properties can be measured wit
evablogger [386]

Answer:

\boxed {\sf Physical}

Explanation:

There are two main kinds of properties: chemical and physical.

Chemical properties, like the name suggests, have to be observed by changing the chemical composition.

That leaves <u>physical properties.</u> They can be measured without any chemical composition changes.

Some examples include: color, odor, mass, density, and volume. All can be measured with just the senses or measuring tools and no composition alterations are needed.

3 0
3 years ago
Read 2 more answers
Write a balanced chemical equation for the fermentation sucrose (C12H22O11) by yeasts in which the aqueous ethyl alcohol (C2H5OH
kodGreya [7K]

Answer:

C12H22O11(aq) + H2O(l) —> 4C2H5OH(aq) + 4CO2(g)

Explanation:

When aqueous sugar (sucrose) react with water in the presence of yeast, the following products are obtained as shown in the equation below:

C12H22O11(aq) + H2O(l) —> C2H5OH(aq) + CO2(g)

Now, we shall balance the equation as follow:

There are a total of 24 atoms of H on the left side and 6 atoms on the right side. It can be balance by putting 4 in front of C2H5OH as shown below:

C12H22O11(aq) + H2O(l) —> 4C2H5OH(aq) + CO2(g)

There are a total of 9 atoms of C on the right side and 12 atoms on the left side. It can be balance by putting 4 in front of CO2 as shown below:

C12H22O11(aq) + H2O(l) —> 4C2H5OH(aq) + 4CO2(g)

Now the equation is balanced.

8 0
3 years ago
What would the word equation be?
valentinak56 [21]
The problem=the equation
5 0
3 years ago
Balance the chemical equation.Au plus HC l plus HNO 3 right arrow AuC l Subscript 3 Baseline plus NO plus Upper H 2 Upper OAu+HC
tino4ka555 [31]

Answer:

Au+ 3HCl + HNO_3 \to AuCl_3+NO+2H_2O

Explanation:

Chemical Equations are representations of chemical reactions in terms of the symbols and formulae of the elements and compounds involved. A chemical equation usually have the reactant at the left hand side while the product is on the right hand side.

A chemical Equation is of little or no value if is not in balanced equation. When an equation is balanced , the total number of atoms of any element on the left-hand side of it must be equal to the total number of atoms of that element on the right hand side.

in the given question; we are given a word problem of chemical symbol to  compute and also to balance the chemical equation.

From below; the chemical equation can be written as:

Au+ HCl + HNO_3 \to AuCl_3+NO+2H_2O

From the above  equation we will notice  that  it is not truly balanced ; so th balanced equation can be written as:

Au+ 3HCl + HNO_3 \to AuCl_3+NO+2H_2O

5 0
3 years ago
The number of grams of H2 in 1470 mL of H2 gas. ​
Lorico [155]

Answer:

0.1313 g.

Explanation:

  • It is known that at STP, 1.0 mole of ideal gas occupies 22.4 L.
  • Suppose that hydrogen behaves ideally and at STP conditions.

<u><em>Using cross multiplication:</em></u>

1.0 mol of hydrogen occupies → 22.4 L.

??? mol of hydrogen occupies → 1.47 L.

∴ The no. of moles of hydrogen that occupies 1.47 L = (1.0 mol)(1.47 L)/(22.4 L) = 6.563 x 10⁻² mol.

  • Now, we can get the no. of grams of hydrogen in 6.563 x 10⁻² mol:

<em>The no. of grams of hydrogen = no. of hydrogen moles x molar mass of hydrogen</em> = (6.563 x 10⁻² mol)(2.0 g/mol) = <em>0.1313 g.</em>

5 0
3 years ago
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