All categories

3 years ago

A bag contains different colored candies. There are 50 candies in the bag, 28 are red, 10 are blue, 8 are green and 4 are

Mathematics

1 answer:

kozerog [31]3 years ago

7 0

I think it 5:50 but it could also be 3:50 and 2:50

You might be interested in

What is the value of 6(2b-4) when b =5

kondor19780726 [428]

6(2(5)-4)= 6(10-4)= 6(6)=36 so your answer is 36

5 0

2 years ago

Read 2 more answers

The discriminant of a quadratic equation is -7. Classify the number and type of roots.

lyudmila [28]

Hello,

Answer D.
====================

5 0

3 years ago

Andre says that 5 3/4 + 2 1/4 = 7 1/2 because 7 4/8 = 7 1/2. Identify his mistake. Draw a picture to prove that he is wrong.

MA_775_DIABLO [31]

Answer:

Step-by-step explanation:

The given expression is

$5\frac{3}{4}+2\frac{1}{4} =7\frac{4}{8}=7\frac{1}{2}$

We will rewrite the expression

$\frac{23}{4}+\frac{9}{4} =\frac{60}{8}=7\frac{1}{2}$

When we add the fraction

$\frac{23+9}{4}$ = $\frac{32}{4}$ = 8

While Andre says the answer is $7\frac{1}{2}$

because Andre added the denominator where he has to make a common denominator that should be 4 instead of 8.

Andre made mistake in this step

Picture is given below :

3 0

3 years ago

For what values of θ is sinθ < cosθ when 0 ≤ θ < π ?

zysi [14]

<h3>Answer: $0 \le \theta < \frac{\pi}{4}$ </h3>

=========================================================

How to get this answer:

Use the unit circle to note that $\sin\theta = \cos\theta = \frac{\sqrt{2}}{2}$ when $\theta = \frac{\pi}{4}$ (aka 45 degrees)

Beyond this point, cosine is smaller than sine. This means that anything from 0 to pi/4 will have sine be smaller than cosine. It might help to graph y = sin(x) and y = cos(x) on the interval from x = 0 to x = pi.

The two curves y = sin(x) and y = cos(x) intersect at the point $\left(\frac{\pi}{4}, \frac{\sqrt{2}}{2}\right)$

-------------------------------

Here's a more detailed picture of whats going on.

$\sin \theta < \cos \theta\\\\\sin \theta < \sqrt{1-\sin^2\theta}\\\\\sin^2 \theta < 1-\sin^2\theta \\\\2\sin^2 \theta < 1\\\\\sin^2 \theta < \frac{1}{2}\\\\\sin \theta < \sqrt{\frac{1}{2}}\\\\\sin \theta < \frac{1}{\sqrt{2}}\\\\\sin \theta < \frac{\sqrt{2}}{2}\\\\\theta < \arcsin\left(\frac{\sqrt{2}}{2}\right)\\\\\theta < \frac{\pi}{4}\\\\$

Intersect the intervals $0 \le \theta < \pi$ and $\theta < \frac{\pi}{4}$ and you'll end up with the final answer $0 \le \theta < \frac{\pi}{4}$

4 0

2 years ago

In "The Emperor's New Clothes" what does the opening tell you about the narrator?

Nataly [62]

Answer:

third person

Step-by-step explanation:

4 0

2 years ago