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Y_Kistochka [10]
3 years ago
5

Helpie plz my teacher wont answer me

Mathematics
1 answer:
GaryK [48]3 years ago
5 0

Answer:

45d + 42

Step-by-step explanation:

-7(-7d - 6) - 4d

49d + 42 - 4d

49d - 4d + 42

45d + 42

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How to turn 9/6 into a mixed number
brilliants [131]
You can turn 9/6 into a mixed number by doing it 2 ways:
9/6=1 3/6 or 1 1/2
<span>Or you can simplify it to 3/2 to make it easier to form into a mixed number. 1 1/2

Hope this helped :)</span>
3 0
3 years ago
Please help me, I don’t know what i am doing
lara31 [8.8K]

Answer:

y=mx+b

Step-by-step explanation:

mark brainliest

4 0
2 years ago
A city has a populationof 370,000 people. Suppose that each year the population grows 7%. What will the population be after 8 ye
maksim [4K]

Answer:

577,220 will be the population I think

Step-by-step explanation:

370,000/100=3700=1%

3,700*7=25,900

25,900*8=207,200

370,000+207,200=577,220

3 0
3 years ago
Bill wanted to try out different water craft he went 62 mikes downstream in a motor boat and 27 mikes down stream on a jest ski
valina [46]

Answer:

The speed on motorboat is 20 mph

Step-by-step explanation:

here, we want to find the speed on the motorboat

if he has a speed of x mph on the motor boat, his speed on the ski will be (x + 10) mph

The total hours is 4 hours

Mathematically; speed = distance/time

Time on ski is 27/x+ 10

Time on motor boat is 62/x

The addition of both is 4

Thus;

27/(x + 10) + 62/x = 4

27(x) + 62(x + 10) = 4(x)(x + 10)

27x + 62x + 620 = 4(x^2 + 10x)

89x + 620 = 4x^2 + 40x

4x^2 -49x-620 = 0

using the quadratic formula;

{-b ± √(b^2-4ac)}/2a

where a = 4, b = -49 and c = -620

= 49 ± √(-49)^2-4(4)(-620)/8

So we have

49+ 111/8 or 49-111/8

Speed cannot be negative

(49 + 111)/8

= 20 mph

3 0
2 years ago
Evaluate C_n.xP^xQn-x For the given n=7, x=2, p=1/2
r-ruslan [8.4K]

Answer:

The value of given expression is \frac{21}{128}.

Step-by-step explanation:

Given information: n=7, x=2, p=1/2

q=1-p=1-\frac{1}{2}=\frac{1}{2}

The given expression is

C(n,x)p^xq^{n-x}

It can be written as

^nC_xp^xq^{n-x}

Substitute n=7, x=2, p=1/2 and q=1/2 in the above formula.

^7C_2(\frac{1}{2})^2(\frac{1}{2})^{7-2}

\frac{7!}{2!(7-2)!}(\frac{1}{2})^2(\frac{1}{2})^{5}

\frac{7!}{2!5!}(\frac{1}{2})^{2+5}

\frac{7\times 6\times 5!}{2\times 5!}(\frac{1}{2})^{2+5}

21(\frac{1}{2})^{7}

\frac{21}{128}

Therefore the value of given expression is \frac{21}{128}.

7 0
3 years ago
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