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3 years ago

15

Doug had about $3,215 in savings while his brother had double that amount in savings. What is a reasonable amount that the broth

ers have saved? due in 10 mins

1 answer:

swat323 years ago

4 0

Since Doug’s brother has double the amount of Doug we can just multiply the amount Doug has by 2.

$3,215*2 = $6,430

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. Lola sells jewelry. She sold 6 necklaces.She sells each necklace for $9.She spent $14 on supplies to make the necklaces. Write

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(6 necklaces x $9 per necklace) - $14 spent on supplies = profit for Lola

or (6 x 9) - 14 = profit for Lola

The actual profit is $40.

Step-by-step explanation:

First, you need to calculate how much money Lola made from selling jewelry. She sold 6 necklaces, and each one was sold for $9, so you can calculate the total sale proceeds by multiplying 6 x $9 = $54.

However, you then have to subtract the cost of supplies that Lola had to buy to make the necklaces, in order to find out how much money Lola actually made. Therefore, subtract $14 from the calculation above.

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3 years ago

Make 'h' as the subject. Remember to rationalize the denominator while solving.

Sliva [168]

Hello there BeGuiLE !

To solve your question, we must first bring 'h' to one side of the equation. Let's bring all the terms with the variable 'h' to the left side of the equation. So,
$\large{\sf\sqrt{ 3 } h = 1.6+h}$
→ $\large{\sf\sqrt{3}h-h=1.6 }$

Now, let's combine the 2 terms containing the variable 'h'.
$\large{\sf\sqrt{3}h-h=1.6 }$
→ $\large{\sf\left(\sqrt{3}-1\right)h=1.6 }$

Now, we need to leave the variable 'h' alone in the left side of the equation & bring (√3 + 1) to the other side of the equation. This is done in order to make 'h' as the subject of the equation. So, we'll get it as,
$\large{\sf\left(\sqrt{3}-1\right)h=1.6 }$
→ $\large{\sf\:h=\frac{1.6}{\sqrt{3}-1} }$

Now, let's rationalize it. Rationalizing is a process where we move the root from the denominator of a fraction to the numerator for easier calculation. So,
$\large{\sf\:h=\frac{1.6}{\sqrt{3}-1} }$
→ $\large{\sf\:h=\frac{1.6(\sqrt{3}+1)}{(\sqrt{3}-1 )(\sqrt{3}+1}) }$
Now, use the algebraic identity, (a + b)(a - b) = a² - b²
→ $\large{\sf\:h=\frac{1.6(\sqrt{3}+1)}{3-1} }$
→ $\large{\sf\:h=\frac{1.6(\sqrt{3}+1)}{2} }$
→ $\boxed{\large{\sf\:h=0.8(\sqrt{3}+1)}}$

Now, we've made 'h' as the subject of the equation. If you want to solve it more, then,
$\large{\sf\:h=0.8(\sqrt{3}+1)}$
Take √3 as 1.73 (approx. value up to 2 decimal places)
→ $\large{\sf\:h=0.8(1.73+1)}$
→ $\large{\sf\:h=0.8(2.73)}$
→ $\boxed{\boxed{\huge{\bf{\:h=2.184 \: (approx.)}}}}$

I hope this will help you.

Please refer to the attached image if the explanation shows some error.

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Check out more links which will help you understand the topic better :

■ brainly.com/question/21406377

■ brainly.com/question/696184

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