Like dissolves like
so water is polar
CCl4 is nonpolar
LiCl is polar
CH4 is nonpolar
PCl6 is nonpolar
so LiCl would dissolve
Explanation:
The given data is as follows.
Volume = 1 L, Concentration of Ca = 5 ppm or 5 mg/L
As 1 mg = 0.001 g so, 5 mg /L will be equal to 0.005 g/l. Molar mass of calcium is 40.078 g/mol.
Hence, calculate molarity of calcium as follows.
Molarity of Ca = 
= 
Molarity of Ca = 
Hence, molarity of 
is . Since, volume is same so, moles of calcium chloride will be 
.
Thus, we can conclude that mass of will be as follows.
(molar mass of = 110.984 g/mol)
= 0.0138 g
Thus, we can conclude that mass of is 0.0138 g.
<h3>Answer:</h3>
Molar Mass = 56 g.mol⁻¹
<h3>Explanation:</h3>
Data Given:
Mass = 5.00 μg = 5.0 × 10⁻⁶ g
Number of Molecules = 5.38 × 10¹⁶ Molecules
Step 1: Calculate Moles of 1-Butene:
As we know one mole of any substance contains 6.022 × 10²³ particles (atoms, ions, molecules or formula units). This number is also called as Avogadro's Number.
The relation between Moles, Number of Particles and Avogadro's Number is given as,
Number of Moles = Number of Particles ÷ 6.022 × 10²³
Putting values,
Number of Moles = 5.38 × 10¹⁶ Molecules ÷ 6.022 × 10²³
Number of Moles = 8.93 × 10⁻⁸ Moles
Step 2: Calculate Molar Mass of 1-Butene:
As,
Mole = Mass ÷ M.Mass
Solving for M.Mass,
M.Mass = Mass ÷ Mole
Putting values,
M.Mass = 5.0 × 10⁻⁶ g ÷ 8.93 × 10⁻⁸ mol
M.Mass = 55.99 g.mol⁻¹ ≈ 56 g.mol⁻¹
Answer:
The answer is Graph A, because there is a direct relationship between pressure and volume.
The volume of a given gas sample is directly proportional to its absolute temperature at constant pressure.
