the best option would be d.) examples of constructive erosion.
The two elements are in the same period, with Element R the first element in the period and Element Q the last element.
Draw a velocity-time diagram as shown below.
Because a velocity of 26.82 m/s is attained in 4.00 s from rest, the average acceleration is
a = 26.82/4 = 6.705 m/s²
The time required to reach maximum velocity of 82.1 m/s is
t₁ = (82.1 m/s)/(6.705 m/s²) = 12.2446 s
The distance traveled during the acceleration phase is
s₁ = (1/2)at₁²
= (1/2)*(6.705 m/s²)*(12.2446 s)²
= 502.64 m
Answer:
The time required to reach maximum speed is 12.245 s
The distance traveled during the acceleration phase is 502.6 m
Answer:Given:
Initial speed of fugitive, v0 = 0 m/s
Final speed, vf = 6.1 m/s
acceleration, a = 1.4 m/s^2
Speed of train, v = 5.0 m/s
Solution:
t = (vf-v0)/a
t = (6.1-0)/1.4
t =4.36 s
Distance traveled by train, x_T =v*t
x_T =5*4.36 = 21.8 m
Distance travelled by fugitive, x_f = v0*t+1/2at^2
x_f = 0*4.36+1/2*1.4*4.36^2
x_f =13.31 m
5*t = v(t-4.36)+x_f
5*t=6.1*(t-4.36)+13.31
solve for t, we get
t = 12.08 s
The fugitive takes 12.08 s to catch up to the empty box car.
Distance traveled to reach the box car is
X_T = v*t
X_T = 5*12.08 s
X_T = 60.4 m
Explanation:
Answer:
t=62 s
Explanation:
Applying the conservation of linear momentum formula:

the initial velocity is zero, we can calculate the man's mass using the gravitational force formula:

now:

That is 0.13m/s due south.
because there is no friction, the man will maintain a constant velocity, so:
