1answer.
Ask question
Login Signup
Ask question
All categories
  • English
  • Mathematics
  • Social Studies
  • Business
  • History
  • Health
  • Geography
  • Biology
  • Physics
  • Chemistry
  • Computers and Technology
  • Arts
  • World Languages
  • Spanish
  • French
  • German
  • Advanced Placement (AP)
  • SAT
  • Medicine
  • Law
  • Engineering
xxMikexx [17]
3 years ago
11

If you wish to take a picture of a bullet traveling at 500 m/s, then a very brief flash of light produced by an RC discharge thr

ough a flash tube can limit blurring. Assuming 1.00 mm of motion during one RC constant is acceptable, and given that the flash is driven by a 503 µF capacitor, what is the resistance in the flash tube?
Physics
2 answers:
Agata [3.3K]3 years ago
8 0

Answer:

Resistance in the flash tube, R=3.97\times 10^{-3}\ \Omega

Explanation:

It is given that,

Speed of the bullet, v = 500 m/s

Distance between one RC constant, d = 1 mm = 0.001 m

Capacitance, C=503\ \mu F=503\times 10^{-6}\ F

The time constant of RC circuit is given by :

\tau=RC

R is the resistance in the flash tube

R=\dfrac{\tau}{C}..........(1)

Speed of the bullet is given by total distance divided by total time taken as :

v=\dfrac{d}{\tau}

\tau=\dfrac{d}{v}

\tau=\dfrac{0.001}{500}

\tau=0.000002\ s

Equation (1) becomes :

R=\dfrac{0.000002}{503\times 10^{-6}}

R=3.97\times 10^{-3}\ \Omega

So, the resistance in the flash tube is 3.97\times 10^{-3}\ \Omega. Hence, this is the required solution.

Oksi-84 [34.3K]3 years ago
8 0

Answer:

R=3.98\times 10^{-3} ohm

Explanation:

We are given that

Speed of bullet=500 m/s

Distance during one  RC time constant=d=1 mm=1\times 10^{-3} m

Capacitance=503\mu F=503\times 10^{-6} F

We have to find the resistance in the flash tube.

\tau=\frac{d}{v}=\frac{1\times 10^{-3}}{500}

\tau=2\times 10^{-6} s

\tau =RC

R=\frac{\tau}{C}=\frac{2\times 10^{-6}}{503\times 10^{-6}}

R=3.98\times 10^{-3} ohm

Hence, the resistance in the flash tube=3.98\times 10^{-3} ohm

You might be interested in
A pressure cylinder has a diameter of 150-mm and has a 6-mm wall thickness. What pressure can this vessel carry if the maximum s
myrzilka [38]

Answer:

p = 8N/mm2

Explanation:

given data ;

diameter of cylinder =  150 mm

thickness of cylinder = 6 mm

maximum shear stress =  25 MPa

we know that

hoop stress is given as =\frac{pd}{2t}

axial stress is given as =\frac{pd}{4t}

maximum shear stress = (hoop stress - axial stress)/2

putting both stress value to get required pressure

25 = \frac{ \frac{pd}{2t} -\frac{pd}{4t}}{2}

25 = \frac{pd}{8t}

t = 6 mm

d = 150 mm

therefore we have pressure

p = 8N/mm2

7 0
3 years ago
Measuring spoons are used when measuring<br>less than how much?​
Step2247 [10]

Measuring spoons are used when measuring less than 1/4 cup

8 0
3 years ago
The change in momentum of an object is equal to the Question 4 options: Force acting on it times its velocity. impulse acting on
lesya [120]

Answer:

impulse acting on it

Explanation:

The impulse is defined as the product between the force applied to an object (F) and the time interval during which the force is applied (\Delta t):

I=F\Delta t

We can prove that this is equal to the change in momentum of the object. In fact, change in momentum is given by:

\Delta p = m \Delta v

where m is the mass and \Delta v is the change in velocity. Multiplying and dividing by \Delta t, we get

\Delta p = m \frac{\Delta v}{\Delta t} \Delta t

and since \frac{\Delta v}{\Delta t} is equal to the acceleration, a, we have

\Delta p = ma \Delta t

And since the product (ma) is equal to the force, we have

\Delta p = F \Delta t

which corresponds to the impulse.

5 0
3 years ago
Calculate the energy gained by an ice block in the following experiment.
MAXImum [283]

The heat is exchanged when two different temperature objects come in contact. The energy gained by an ice block is 2.3 Joules.

<h3>What is temperature?</h3>

Temperature is the degree of hotness and coldness of the object.

A 7g block of ice was added to a coffee cup full of 103.4 grams of water. The water had an initial temperature T₁ = 24.5 C and a final temperature T₂ = 19.2 C after all the ice had melted.

Heat lost by water = Heat gained by ice

Qgain = ms(T₂ -T₁ )

Substituting the value for mass of water m =103.4 g= 0.1034 kg , specific heat of water s = 4.18 kJ/kg and temperature values, we get

Qgain = 0.1034 x 4.18 x (24.5 - 19.2)

Qgain = 2.3 Joules

Thus, the energy gained by an ice block is 2.3 Joules.

Learn more about temperature.

brainly.com/question/20459283

#SPJ1

7 0
2 years ago
State whether the following statement are true or false .
Klio2033 [76]
1. It’s true
4 ,7 ,8 is correct
5 0
3 years ago
Other questions:
  • I Need help please with this question..
    15·1 answer
  • What is isostasy dependent on a balance between
    10·2 answers
  • Summarize the steps you might use to carry out an investigation using scientific methods
    6·1 answer
  • A ball is thrown upwards at a velocity of 20.2m/s at what time will the ball reach its highest point
    15·1 answer
  • Does anyone know what Base jump is?
    14·1 answer
  • Only two electrons, with opposing spins, are allowed in each orbital is known as the
    5·1 answer
  • Based on Archimedes' principle, the greatest buoyant force an object can experience in water is determined by which quantity?
    12·1 answer
  • A 0.0121-kg bullet is fired straight up at a falling wooden block that has a mass of 4.99 kg. The bullet has a speed of 898 m/s
    10·1 answer
  • 2) How many significant figures are in the number 0.0037010?<br>​
    8·1 answer
  • The compass uses a pendulous system to improve?
    11·1 answer
Add answer
Login
Not registered? Fast signup
Signup
Login Signup
Ask question!