Well, let’s find the initial velocity first:
Vf = Vi + at
0 = Vi - 9.8*2
0 = Vi - 19.6
Vi = 19.6 m/s
We know the final velocity is 0 because when it hits it’s peak, it’s at 0 m/s.
So now use this kinematic equation to find the final position:
Yf = Yi + Vi*t + 1/2a*t^2
Yf = 0 + 19.6(2) - 4.9(2^2)
Yf = 39.2 - 19.6
Yf = 19.6 meters
If you have any questions for how I derived anything, just lemme know. Most of the info requires thinking and imagining of the situation. I assumed you know gravity is 9.8 and you’re expected to assume velocity is 0 at peak height
Answer:
The drawing of the free body diagram is in the attachment.
Explanation:
In order to draw a<em> free body diagram</em>, you have to include in the drawing all the acting forces in the box for the given situation.
The acting forces are:
-The normal force (N), which is the contact force that the inclined plane applies to the box. This force is perpendicular to the contact surface.
-The weight force (W), which is due to the force of gravity on the box. The direction of the weight force is vertical (perpendicular to the ground)
-The friction force (Fs), which in this case is the static friction force because the box is in rest. The direction of this force is opposite to the direction of the movement.
Therefore, you have to draw the inclined plane, the box and the acting forces (See the attachment)
Answer:
June Mar Fajardo
plus he plays for Phillipines men's national basketball team
and baseball is my favorite team sport because everyone has a role no matter how big or small it is
B. because it's kind of like a fulcrum.