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Ilia_Sergeevich [38]
3 years ago
11

Question 5 please and thank you

Mathematics
1 answer:
stira [4]3 years ago
6 0
Need a more clear photo please can’t see nothing.
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Can someone do #1 and #2 I don't really get the answer. My teacher hasn't explain anything. He just gave us the paper and we got
Elenna [48]
1) f(x) + g(x)

= 7√x + 4 + 2√x - 2

= √x(7 + 2) + 2

= 9√x + 2  [ Final Answer ]

2) f(x) - g(x)

= 7√x + 4 - (2√x - 2)

= 7√x + 4 - 2√x + 2

= √x(7 - 2) + 6

= 5√x + 6   [ Final Answer ]

Hope this helps!
5 0
3 years ago
4y-28 pls help find y value
mina [271]

Answer:

4y-28 = 0

4y = 28

y=28/4

y = 7

5 0
3 years ago
Read 2 more answers
Helppppppp:))) Pls :)))))))
Umnica [9.8K]

Answer:

the handle will end up on the left side

Step-by-step explanation:

The cup is rotated 180 degrees clockwise. Therefore, I assume the rotation is about the center of the bottom of the cup. Also, only the cup is rotated, not the saucer (although this makes no difference in this problem).

The result is that the handle will end up on the left side. The cup will still be right side up.

8 0
3 years ago
Read 2 more answers
Four friends bought tickets to the school play if it cost them a total of $28 find how much each friend paid?
galina1969 [7]

Answer:

28:4=7

Pls mark as brainliest

8 0
3 years ago
Please solve equations by completing square
BlackZzzverrR [31]
x^2-4x+1=0\\
x^2-4x+4-3=0\\
(x-2)^2=3\\
|x-2|=\sqrt3\\
x-2=\sqrt3 \vee x-2=-\sqrt3\\
x=2+\sqrt3 \vee x=2-\sqrt3

x^2+6x-9=0\\
x^2+6x+9-18=0\\
(x+3)^2=18\\
|x+3|=\sqrt{18}=3\sqrt2\\
x+3=3\sqrt2 \vee x+3=-3\sqrt2\\
x=-3+3\sqrt2 \vee x=-3-3\sqrt2\\

x^2+20x+3=0\\
x^2+20x+100-97=0\\
(x+10)^2=97\\
|x+10|=\sqrt{97}\\
x+10=\sqrt{97} \vee x+10=-\sqrt{97}\\
x=-10+\sqrt{97} \vee x=-10-\sqrt{97}

x^2-2x-5=0\\
x^2-2x+1-6=0\\
(x-1)^2=6\\
|x-1|=\sqrt6\\
x-1=\sqrt6 \vee x-1=-\sqrt6\\
x=1+\sqrt6 \vee x=1-\sqrt6
8 0
4 years ago
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