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3 years ago

The area of a square is 81 square centimeters. Find the length of a side. Find the length of the diagonal.

Mathematics

1 answer:

Nataly_w [17]3 years ago

4 0

Side would be 9centimeters diagonal is 12.7 centimeters

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To make a specific shade of green paint, Timia mixes 2 cups of blue paint with 10 cups of yellow point. How many cups of yellow

7nadin3 [17]

Answer:

1 cup of blue paint required 5 cups of yellow paints

Step-by-step explanation:

Given

2 cups of blue = 10 cups of yellow

Required

Determine the number of cups of yellow for 1 cup of blue paint

The given parameter shows a linear relationship between paints of blue and paints of yellow

We have:

2 cups of blue = 10 cups of yellow

Multiply both sides by 0.5

0.5* 2 cups of blue = 0.5* 10 cups of yellow

1 cup of blue = 5 cups of yellow

Hence;

1 cup of blue paint required 5 cups of yellow paints

7 0

4 years ago

7divided by 43.4 pls help

Vikki [24]

0.161 (they said explain it so)

8 0

3 years ago

Which equation has a solution of n = 4?

Allushta [10]

Answer:

D. 7n = 28

Step-by-step explanation:

Let's substitute 4 for n in each equation to check if it the resulting equation is correct:

$6+n=24\\ 6+4=24\\ 10\neq 24\rightarrow \text{Incorrect!}$

$5n=54\\5(4)=54\\20\neq54\rightarrow\text{Incorrect!}$

$12-n=16\\12-4=16\\8\neq16\rightarrow\text{Incorrect!}$

$7n=28\\7(4)=28\\28=28\rightarrow\text{Correct!}$

Therefore the answer is D

4 0

2 years ago

Read 2 more answers

Find the equation of the locus of a point that moves so that its distance from the line 12x-5y-1=0 is always 1 unit.

leonid [27]

Answer-

The equations of the locus of a point that moves so that its distance from the line 12x-5y-1=0 is always 1 unit are

$12x-5y+14=0 \\ 12x-5y-14=0$

Solution-

Let a point which is 1 unit away from the line 12x-5y-1=0 is (h, k)

The applying the distance formula,

$\Rightarrow \left | \frac{12h-5k-1}{\sqrt{12^2+5^2}} \right |=1$

$\Rightarrow \left | \frac{12h-5k-1}{\sqrt{169}} \right |=1$

$\Rightarrow \left | \frac{12h-5k-1}{13} \right |=1$

$\Rightarrow 12h-5k-1=\pm 13$

$\Rightarrow 12h-5k=\pm 14$

$\Rightarrow 12h-5k=14,\ 12h-5k=-14$

$\Rightarrow 12h-5k-14=0,\ 12h-5k+14=0$

$\Rightarrow 12x-5y-14=0,\ 12x-5y+14=0$

Two equations are formed because one will be upper from the the given line and other will be below it.

4 0

3 years ago

18.194 rounded to the nearest hundredths

ehidna [41]

18.19
-you're welcome

5 0

3 years ago

Read 2 more answers