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Finger [1]
3 years ago
13

6.

Mathematics
1 answer:
madam [21]3 years ago
8 0

Answer:

  $12.92

Step-by-step explanation:

The total being split 3 ways is ...

  $32.85 × (1 + 0.18) = $38.76

So each pays ...

  $38.76 / 3 = $12.92 . . . amount each person pays

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The length of one side of a square is 3m^4. What is the area of the square? (A = I x w)
wariber [46]
<h3>Answer: Choice C)  9m^8</h3>

============================================================

Explanation:

Each side of the square is the same, so we have length = width in this case.

Length = 3m^4

Width = 3m^4

Area = (length)*(width) = (3m^4)*(3m^4) = (3*3)*(m^4*m^4) = 9m^8

Note how m^4*m^4 leads to m^8. We add the exponents.

The general rule is a^b*a^c = a^(b+c).

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3 years ago
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Find the distance between 6,-2 and 1,-2​
lesantik [10]

The distance between (6,-2) and (1,-2) is 5.

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Please solve!!!!!!!!!!!!!!
Ainat [17]
The answer is b. 7 is greater than or equal to 6.
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4 years ago
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In humans wavy hair(W) is dominant over straight(w). Dark hair(D) dominates red(d).A wavy dark haired male(heterozygous dominant
olga_2 [115]

Answer:

1/4

Step-by-step explanation:

Parents            WwDd                                        wwdd

Gametes  WD   Wd   wD  wd                       wd wd wd wd

Offspring possibilities: WwDd WwDd WwDd WwDd

                                     <u>Wwdd</u> <u>Wwdd</u> <u>Wwdd</u> <u>Wwdd</u>

                                      wwDd wwDd wwDd wwDd

                                      wwdd wwdd wwdd wwdd

P (wavy red hair) =4/16 = 1/4

                 

5 0
3 years ago
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The daily revenue at a university snack bar has been recorded for the past five years. Records indicate that the mean daily reve
faltersainse [42]

Answer: 0.9938

Step-by-step explanation:

Let x be the random variable that represents the daily revenue at a university snack bar.

As per given , we have

\mu=2700 , \sigma=400 and n= 100

Using formula z=\dfrac{x-\mu}{\dfrac{\sigma}{\sqrt{n}}} ,

z-score for x= 2600

z=\dfrac{2600-2700}{\dfrac{400}{\sqrt{100}}}=-2.5

The probability that the average daily revenue of the sample is higher than $2600 :

P(x>2600)=P(z>-2.5)=P(z   [P(Z>-z)=P(Z<z)]

=0.9937903\approx0.9938

Therefore, the probability that the average daily revenue of the sample is higher than $2600 = 0.9938

8 0
3 years ago
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