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aalyn [17]
3 years ago
11

Why does the LL theorem hold for proving right triangles congruent?

Mathematics
2 answers:
Rufina [12.5K]3 years ago
5 0
B.) The right angle is included between the legs.
alina1380 [7]3 years ago
3 0

Answer:

(A) The legs in right triangles are equal.

Step-by-step explanation:

LL theorem or Leg-Leg theorem: The LL theorem is also known as the leg-leg theorem. It states that if the legs of one right triangle are congruent to the legs of another right triangle, then the triangles are congruent.

Thus, in order to prove that the two right triangles are congruent,w use the LL theorem which holds that The legs in right triangles are equal.

Hence, option A is correct.

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It will need around 26138.050... and more it is not a repeating decimal I just simplified it.

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What is -1.2 times 1 1/5 divided by 3/10
djyliett [7]

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-1.2 * 1 1/5 / 3/10

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Please!!! Help!!! Brainliest of Right! it goes as 50 point in the end but i used 100 point if you help me i will help you!!
vekshin1

Answer:

2.  3.913 kg (3 dp)

3.  light cream

4.  240 CoffeeStops

5.  7 CoffeeStops per square mile

6.  2,861 cups of coffee each day

Step-by-step explanation:

Given:

  • Skim milk density at 20 °C = 1.033 kg/l
  • Light cream density at 20 °C = 1.012 kg/l
  • 1 liter = 0.264 gallons

<u>Question 2</u>

\begin{aligned}\textsf{1 gallon} & = \sf \dfrac{1}{0.264}\:liters\\\\\implies \textsf{Mass (1 gallon of skim milk)} & = \sf Density \times Volume\\& = \sf 1.033\:kg/l \times \dfrac{1}{0.264}\:l\\& = \sf 3.913\:kg\:(3\:dp)\end{aligned}

Therefore, the mass of 1 gallon of skim milk is 3.913 kg (3 dp)

---------------------------------------------------------------------------------------------

<u>Question 3</u>

Given:

  • Volume of liquid = 9 liters
  • Mass of liquid = 9.108 kg

\begin{aligned}\implies \sf Density & = \sf \dfrac{Mass}{Volume}\\\\& = \sf \dfrac{9.108\:kg}{9\:l}\\\\& = \sf 1.012\:kg/l \end{alilgned}

Therefore, the container holds light cream.

---------------------------------------------------------------------------------------------

<u>Question 4</u>

Given:

  • 15 CoffeeStops per 100,000 people
  • Population of Manhattan ≈ 1,602,000 people

\begin{aligned}\implies \textsf{Number of Coffeestops} & = \sf \dfrac{population}{density}\\\\& = \sf \dfrac{1,602,000}{100,000/15}\\\\& = \sf \dfrac{1,602,000}{100,000} \times 15\\\\& = \sf 240.3\end{aligned}

Therefore, there are 240 CoffeeStops.

---------------------------------------------------------------------------------------------

<u>Question 5</u>

Given

  • Manhattan ≈ 34 square miles

\begin{aligned}\implies \textsf{CoffeeStops density} & = \sf \dfrac{number\:of\:stores}{land\:area}\\\\& = \sf \dfrac{240}{34}\\\\& \approx \sf 7 \: \textsf{CoffeeStops per square mile}\end{aligned}

Therefore, the density of CoffeeStops is 7 per square mile.

---------------------------------------------------------------------------------------------

<u>Question 6</u>

Given:

  • Each person buys 3 cups of coffee per week

\begin{aligned}\implies \textsf{Cups served each week} & = \textsf{number of people} \times \textsf{number of cups per week}\\& = \sf 1,602,000 \times 3\\& = \sf 4,806,000\: \textsf{cups per week}\\\\\implies \textsf{Cups per day} & = \sf \dfrac{\textsf{cups per week}}{\textsf{days in a week}}\\\\& = \sf \dfrac{4,806,000}{7}\\\\& = \sf 686,571\:\textsf{(nearest whole number)}\end{aligned}

\begin{aligned}\implies \textsf{Cups served per day per shop} & = \dfrac{\textsf{cups per day}}{\textsf{number of shops}}\\\\& = \sf \dfrac{686,571}{240}\\\\& = \sf 2,861\: \textsf{(nearest whole number)} \end{aligned}

Therefore, each Manhattan CoffeeStop serves approximately 2,861 cups of coffee each day.

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Answer:

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3 0
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Read 2 more answers
Find the equation of the circle with a diameter whose end points are (-1,-2) and (-3,2)
Sergeeva-Olga [200]

Answer:

The equation of the circle with a diameter whose end points are (-1,-2) and (-3,2) is

x^{2} +y^{2}+4x-1=0

Step-by-step explanation:

<u>Explanation:</u>-

<u>Step 1:</u>-

The equation of the circle having center and radius is

(x-h)^2+(y-k)^2=r^2

here center is (h,k) and radius is r

Given diameter whose end points are (-1,-2) and (-3,2)

The diameter of the circle is passing through the center of the circle

so center of the circle = midpoint of two end points

      (\frac{-1 +(-3) }{2} ,\frac{-2+2 }{2}  )

    (-2,0)

therefore center (h,k) = (-2,0)

<u>Step 2:-</u>

we have to find the radius of the circle

the radius of the circle = the distance from center to the one end point

i.e., C P = r

Given one end point is P(-3,2) and center C(-2,0)

The distance formula of two points are

\sqrt{(x_{2}-x_{1} ) ^{2}+ (y_{2}-y_{1} ) ^{2}}

r=\sqrt{{(-3)-(-1) ) ^{2}+ (2-(-2)) ^{2}}

r=\sqrt{5}

<u>Step 3</u>:-

center (h,k) = (-2,0) and

radius r=\sqrt{5}

The standard form of circle equation

(x-h)^2+(y-k)^2=r^2

(x-(-2))^2+(y-0)^2=\sqrt{5} ^2

on simplification is

x^{2} +y^{2}+4 x-1=0

5 0
3 years ago
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