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vlada-n [284]
3 years ago
5

Find the radius or diameter of each circle with the given dimension (Will give brainliest to correct answer)

Mathematics
1 answer:
Firdavs [7]3 years ago
5 0

Answer:

3.14 = pi

1.) R = 1.5 and A = 7.065

2.) D = 28 and A = 615.44

3.) R = 10 and A = 314

Step-by-step explanation:

R = 0.5×d

Area of circle = π×r²

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Robert and Elaine ran around the high school track during gym class. robert ran 1/2 of the way around the track in 5/6 minute. L
jok3333 [9.3K]

<u>Answer</u>


Incorrect


<u>Explanation</u>

Unpack the problem:

Let the distance round the track to be X.

Speed is the ratio of distance to time.

Robert run a distance of (1/2)x

Elaine run a distance of (3/4)x


Make a plan:

Finding the speed of each.

Compare their speeds to determine who ran faster than who.


Solution:

Robert's speed =(1/2)x/(5/6)

=1/2×6/5x

= (3/5)x

= 0.6x

Elaine's speed = (3/4)x/(9/10)

= (3/4)×(10/9)x

= (5/6)x

= 0.83333x



<em>Elaine ran faster than Robert. </em>


<u>Look back and explain:</u>

0.83333x > 0.6x

Elaine's speed is higher than Robert's speed.

This shows that Elaine ran faster than Robert.

5 0
3 years ago
E = MV^2 ÷ 2 + mgh, Make V Subject of the formula​
Stels [109]

Answer:

\red{ \bold{ V = \sqrt{\frac{2(E - mgh)}{M}}}}

Step-by-step explanation:

E = MV^2 ÷ 2 + mgh \\  \\ E - mgh = MV^2 ÷ 2  \\  \\  2(E - mgh)= MV^2   \\  \\  \frac{2(E - mgh)}{M}=V^2  \\  \\  \sqrt{\frac{2(E - mgh)}{M}}  = V \\  \\ \red{ \bold{ V = \sqrt{\frac{2(E - mgh)}{M}}}}

4 0
3 years ago
If 6!+7!+8!=(n)(6!), then the value of n is<br> A) 15<br> B)16<br> C)63<br> D)64<br> E)15!
gladu [14]
6!+7!+8!=(n)(6!)
calculate the individual values first:
6!=720
7!=5040
8!=40320

plug them into the equation:
720+5040+40320=n720
solve for n
5760+40320=n720
46080=n720
divide both sides by 720 to isolate n
46080/720=n720/720
64=n
6 0
3 years ago
Can someone please help me with this question?
vodka [1.7K]

Answer:

Answer is D hope this helps :)

Step-by-step explanation:

8 0
3 years ago
Read 2 more answers
2. Draw the image of ∆RST under the dilation with scale factor ⅓ and center of dilation at the origin. Label the image ∆R’S’T’.
Alchen [17]
Since center of dilation is the origin, this is easy. Just divide all of the x and y coordinate values by 3. Place the new point on the graph, and draw the triangle.

R' = R(3,6)/3 = (3/3,6/3)=(1,2). So R'(1,2)
S' = S(-3,6)/3 = (-3/3,6/3)=(-1,2). So S'(-1,2)
T' = T(-6,-6)/3 = (-6/3,-6/3)=(-2,-2). So T'(-2,-2)

So you now know the location of the 3 new points. R' at (1,2), S' at (-1,2) and T' at (-2,-2). Simply draw those 3 points on your graph and connect the lines to make a new triangle.

6 0
3 years ago
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