A b c d etc. oh well
Are there any choices perhaps? Gracie
the answer is b. hope this helps:))
Explanation:
P₁ = P₂ + ρgh
g is the acceleration due to gravity
ρ is the density of the fluid
h is the depth of the fluid
P₁ is the pressure at that depth
P₂ is the pressure at the surface
P₁ and P₂ can either be absolute pressures or gauge pressures, but they must match.
For example, if you wanted to find the <em>absolute</em> pressure at the bottom of an <em>open</em> tank, you would use P₂ = Patm = 14.7 psi or 101.3 kPa.
If instead you wanted to find the <em>gauge</em> pressure, you would use P₂ − Patm = 0 psi or 0 kPa.
If the tank is sealed and pressurized, you would use the P₂ of the tank.
Answer:
Explanation:
Given that,
Charge through a wire is
Q = 4000C
Time for charge to pass through the wire is
t = 50seconds
Then,
Current through the wire is the rate of charge passing through the wire
Q = it
Where
Q is charge.
I is current
t is time taken
Therefore,
I = Q / t
I = 4000 / 50
I = 80 Amps
Answer:
vi = 2.83 √gR
Explanation:
For this exercise we can use the law of conservation of energy
Let's take a reference system that is at point A, the lowest
Starting point. Lower, point A
Em₀ = Ki = ½ m vi²
Final point. Higher, point B
= K + U
It indicates that at this point the kinetic energy is ki / 2 and the potential energy is ki / 2
K = ki / 2
U = m g (2R)
Energy is conserved so
Em₀ = Em_{f}
½ m vi² = ½ (1/2 m vi²) + m g 2R
½ m vi² (1- ½) = m g 2R
vi² = 4 g 2 R
vi = √ 8gR = 2 √2gR
vi = 2.83 √gR
