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Lapatulllka [165]
3 years ago
11

You are retrieving your boat from the water. as a courtesy to others, when should you pull your boat into a launch lane?

Physics
2 answers:
OLga [1]3 years ago
7 0
The best way to pull the boat in the launch lane is when the towing vehicle has reached the boat ramp as well as the trailer. It is best to retrieve the boat in this manner for it is more appropriate, convenient and it is a way of showing courtesy towards others because it is a proper manner.
xz_007 [3.2K]3 years ago
7 0

Explanation:

Traffic jams on boat ramps can be avoided if everyone follows and practices some common courtesy at the ramp. While retrieving the boat from the water surface, it is a common courtesy to place the boat into the launch area only after the towing vehicle has arrived at the ramp. Drop off the driver and then generously wait wait offshore for your turn. Try to clear up the ramp until the trailer arrives at the ramp. This is a most common practice that every body should follow as a common courtesy to others.

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If something is being carried by westerlies, what direction is it moving??
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7 0
3 years ago
*PHYSICS HELP*
sveta [45]
My calculator is about 1cm thick, 7cm wide, and 13cm long.

Its volume is (length) (width) (thick) = (13 x 7 x 1) = 91 cm³ .

The question wants me to assume that the density of my calculator
is about  the same as the density of water.  That doesn't seem right
to me.  I could check it easily.  All I have to do is put my calculator
into water, watch to see if sinks or floats, and how enthusiastically. 
I won't do that.  I'll accept the assumption.

If its density is actually 1 g/cm³, then its mass is about 91 grams.

The choices of answers confused me at first, until I realized that
the choices are actually 1g, 10² g, 10⁴ g, and 10⁶ g.

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3 0
3 years ago
[ b) The time of reverberation of an empty hall without and with 500 audiences is 1.5 sec and 1.4 sec respectively. Find the rev
Lilit [14]

The reverberation time with 800 audiences is 0.875 seconds.

<h3>Reverberation time with 800 audience</h3>

R₁V₁ = R₂V₂

where;

  • R₁ is the reverberation time with 400 audience
  • R₂ is the reverberation time with 800 audience
  • V₁ is initial volume
  • V₂ is final volume

R₂ = R₁V₁/V₂

R₂ = (1.4 x 500) / 800

R₂ = 0.875 seconds

Thus, the reverberation time with 800 audiences is 0.875 seconds.

Learn more about reverberation time here: brainly.com/question/9278479

#SPJ1

4 0
2 years ago
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